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(14-6)+(6-2)______4* (10-8)-2*2 would it be < > or =?

Pre-Algebra
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<
16 > 4
>

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Other answers:

yep
wrong way sorry > lol
thanks i am not good at < >
i just figured it out yesterday lol
(14-6)+(6-2) < 4*(10-8)-2*2 that is what i got my sis just showed me how
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You wrote the equation wrong at the beginning of your drawing, you wrote (6-2) instead of 6+2. \[(14-6)+(6+2)?(4(10-8)-(2\times2)\] \[(8)+(8)?4(2)-(4)\] \[16?8-4\] \[16?4\] \[16>4\] So the answer is >.
sorry its correct the way i drew it my mistake
was i right then
So you're trying to figure out; \[(14-6)+(6-2)?4(10-8)-2\times2\] instead of the original inequality?
yes sorry
\[(14-6)+(6-2)?4(10-8)-2\times2\] \[(8)+(4)?4(2)-2\times2\] \[12?8-4\] \[12>4\] answer is still >.
what did i do wrong in my picture?
What you did; \[4(10-8)-2\times2\] \[4(2)-2\times2\] \[8\times2-2\] \[16-2\] \[14\] You multiplied 8 by 2 when you should have multiplied 2 with -2; \[4(10-8)-2\times2\] \[4(2)-2\times2\] \[8-2\times2\] \[8-4\] \[4\] Basically you followed the order of operations, but not 100% correctly. 8-2x2 You do multiplication first, but with the -2x2 not switching it around to 8x2-2
You understand? I kind of confused myself with my wording lol
ok thank you soo much that was confusing but understandable than you so much
Yep, no problem.

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