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chevygirl

  • 3 years ago

(14-6)+(6-2)______4* (10-8)-2*2 would it be < > or =?

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  1. jennyjewell25
    • 3 years ago
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    <

  2. 1012G
    • 3 years ago
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    16 > 4

  3. HelpMe94
    • 3 years ago
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    >

  4. HelpMe94
    • 3 years ago
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    yep

  5. jennyjewell25
    • 3 years ago
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    wrong way sorry > lol

  6. chevygirl
    • 3 years ago
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    thanks i am not good at < >

  7. jennyjewell25
    • 3 years ago
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    i just figured it out yesterday lol

  8. chevygirl
    • 3 years ago
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    (14-6)+(6-2) < 4*(10-8)-2*2 that is what i got my sis just showed me how

  9. chevygirl
    • 3 years ago
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    |dw:1351914876861:dw|

  10. chevygirl
    • 3 years ago
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    |dw:1351914986097:dw|

  11. chevygirl
    • 3 years ago
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    |dw:1351915074679:dw|

  12. I4NI
    • 3 years ago
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    You wrote the equation wrong at the beginning of your drawing, you wrote (6-2) instead of 6+2. \[(14-6)+(6+2)?(4(10-8)-(2\times2)\] \[(8)+(8)?4(2)-(4)\] \[16?8-4\] \[16?4\] \[16>4\] So the answer is >.

  13. chevygirl
    • 3 years ago
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    sorry its correct the way i drew it my mistake

  14. chevygirl
    • 3 years ago
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    was i right then

  15. I4NI
    • 3 years ago
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    So you're trying to figure out; \[(14-6)+(6-2)?4(10-8)-2\times2\] instead of the original inequality?

  16. chevygirl
    • 3 years ago
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    yes sorry

  17. I4NI
    • 3 years ago
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    \[(14-6)+(6-2)?4(10-8)-2\times2\] \[(8)+(4)?4(2)-2\times2\] \[12?8-4\] \[12>4\] answer is still >.

  18. chevygirl
    • 3 years ago
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    what did i do wrong in my picture?

  19. I4NI
    • 3 years ago
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    What you did; \[4(10-8)-2\times2\] \[4(2)-2\times2\] \[8\times2-2\] \[16-2\] \[14\] You multiplied 8 by 2 when you should have multiplied 2 with -2; \[4(10-8)-2\times2\] \[4(2)-2\times2\] \[8-2\times2\] \[8-4\] \[4\] Basically you followed the order of operations, but not 100% correctly. 8-2x2 You do multiplication first, but with the -2x2 not switching it around to 8x2-2

  20. I4NI
    • 3 years ago
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    You understand? I kind of confused myself with my wording lol

  21. chevygirl
    • 3 years ago
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    ok thank you soo much that was confusing but understandable than you so much

  22. I4NI
    • 3 years ago
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    Yep, no problem.

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