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cinar
 2 years ago
prove by using epsilondelta definition of limit..
cinar
 2 years ago
prove by using epsilondelta definition of limit..

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cinar
 2 years ago
Best ResponseYou've already chosen the best response.0\[ \lim_{x \rightarrow 0} \sqrt{x}=0\]

cinar
 2 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x} <x<\delta \] how can I show this..

Hero
 2 years ago
Best ResponseYou've already chosen the best response.0i hate epsilondelta definition of a limit

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.0for every \[\epsilon > 0\] there exists a \[\delta > 0\] such that \[\left \sqrt{x}0 \right<\epsilon \] whenever \[0<\left x0 \right<\delta \]
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