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## anonymous 4 years ago prove by using epsilon-delta definition of limit..

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1. anonymous

$\lim_{x \rightarrow 0} \sqrt{x}=0$

2. anonymous

$|\sqrt{x}| <|x|<\delta$ how can I show this..

3. Hero

i hate epsilon-delta definition of a limit

4. sirm3d

for every $\epsilon > 0$ there exists a $\delta > 0$ such that $\left| \sqrt{x}-0 \right|<\epsilon$ whenever $0<\left| x-0 \right|<\delta$

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