Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

vortish

  • 3 years ago

find the area of a triangle that has the height of 4/9 and a base of 1 3/4 and I know to find the area its one half of base times height i need help with the calculations

  • This Question is Closed
  1. AccessDenied
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Well, I'd write it out like this first. \[ A = \frac{1}{2} b h \\ A = \frac{1}{2} \left( 1 \frac{3}{4} \right) \left( \frac{4}{9} \right) \] The mixed number isn't very useful here in multiplication. We should convert it into an improper fraction. \( 1\frac{3}{4} = \frac{3 + 4}{4} = \frac{7}{4} \) \[ A = \frac{1}{2} \left(\frac{7}{4} \right) \left( \frac{4}{9} \right) \\ A = \frac{1\times 7 \times 4}{2 \times 4 \times 9} \] Here, you may cancel the 4's in the numerator and denominator since it's essentially just 4/4= 1 Then just multiply out.

  2. vortish
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so you would come out with an equation it would be 1/2 x 7/9 right

  3. AccessDenied
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    A = 1/2 * 7/9 would be correct, although it would be considered proper to multiply it all together into one fraction.

  4. vortish
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    7/18 or 14/9 i can not remember for the life of me right now sorry

  5. AccessDenied
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    For fractions, we just multiply straight across, numerator-to-numerator, denominator-to-denominator. :) So, 7/(2*9) = 7/18. :)

  6. vortish
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    k thanks

  7. AccessDenied
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You're welcome. :)

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy