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|dw:1351969912033:dw|
Something like this.

yes, thats the case when centre does not line inside circle...

*lie

and i need probability

*centre of square

It is a very good condition! Try to use it in polar system.

Two points with coordinates \((\rho_1,\varphi_1)\) and \((\rho_2,\varphi_2)\).

|dw:1351970854925:dw|

u lost me here....

how square of side 2pi ?

You have only to plot this condition in the square. Please, say something.

|dw:1351972589720:dw|

filled area = 9pi^2/ 8 ?

filled area = \((2\pi-\frac{\pi}2)^2\)

oh, yes....multipled by 2, twice, instead of once....so 9pi^2/16

sorry, 9pi^2/4

Now it is OK.

Now divide it by the area of the whole square and get final probability.

thats 9/16...but i am trying to understand that figure.....

i still don't understand why is the side of square =2pi

randomly with uniform distribution ?

and no.

So what with sniper?

2 quares of side 2R and R ?

Yes. They are concentric circles with radiuses R and 2R.

1/2 right?

@AccessDenied That's right.
Did you get the very first question? About 2 points?

I was not able to get it. I was trying my own method but couldn't figure it out. :(