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swin2013 Group Title

Forces: You discover that it takes 258.0 N to set a 40.0 kg crate in motion on a concrete surface. What is the coefficient of static friction for the crate?

  • 2 years ago
  • 2 years ago

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  1. hubertH Group Title
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    @ swin u need to know what plane u are working on is it an incline plane or an horizontal plane/

    • 2 years ago
  2. hubertH Group Title
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    coefficient of static friction=static frictional force/ normal rection

    • 2 years ago
  3. hubertH Group Title
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    I assume the plane is horizontal: the normal reaction=weight=mg ur

    • 2 years ago
  4. hubertH Group Title
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    got it buddy?

    • 2 years ago
  5. swin2013 Group Title
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    @hubertH it doesn't say. so i assumed it was horrizontal

    • 2 years ago
  6. hubertH Group Title
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    so u knw how to get to the answer right?

    • 2 years ago
  7. swin2013 Group Title
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    but is static friction only involved in inclined plane?

    • 2 years ago
  8. swin2013 Group Title
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    No.. then I wouldn't be asking lol

    • 2 years ago
  9. hubertH Group Title
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    No! static friction is the force required to set the body in motion in our case it 's given as 258.0N

    • 2 years ago
  10. swin2013 Group Title
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    Well they're asking from the coefficient of static friction?

    • 2 years ago
  11. hubertH Group Title
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    coefficient of static friction=static friction force/normal reaction

    • 2 years ago
  12. hubertH Group Title
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    for horizontal plane normal reaction=mg

    • 2 years ago
  13. swin2013 Group Title
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    |dw:1351982204492:dw|

    • 2 years ago
  14. swin2013 Group Title
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    \[mumg?\]

    • 2 years ago
  15. hubertH Group Title
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    |dw:1351982369737:dw|

    • 2 years ago
  16. hubertH Group Title
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    do u now have an idea of what u're doing?

    • 2 years ago
  17. swin2013 Group Title
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    so i say that Fnet = \[\mu _{s} - Fg = ma?\] a little do you?

    • 2 years ago
  18. hubertH Group Title
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    remember u're given the Fs and the mass only

    • 2 years ago
  19. hubertH Group Title
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    there is no Fa, no Fnet

    • 2 years ago
  20. swin2013 Group Title
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    well if it's starting to move wouldn't it be Ff = Mu(s) Fn?

    • 2 years ago
  21. hubertH Group Title
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    \[mus =\frac{ ?Fmus }{Nr ? }\]

    • 2 years ago
  22. swin2013 Group Title
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    I have never used Nr in my FBD before?

    • 2 years ago
  23. hubertH Group Title
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    Nr is ur normal reaction=mg

    • 2 years ago
  24. swin2013 Group Title
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    Ok so it's just normal force (Fn)

    • 2 years ago
  25. swin2013 Group Title
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    so it's Ff/Fn

    • 2 years ago
  26. hubertH Group Title
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    exactly!

    • 2 years ago
  27. swin2013 Group Title
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    and since it's horizontal Fnet = 0N

    • 2 years ago
  28. hubertH Group Title
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    what is Fnet standing fo?

    • 2 years ago
  29. swin2013 Group Title
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    The vector pointing upward

    • 2 years ago
  30. swin2013 Group Title
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    Ok i got it, Mu(s) = .66

    • 2 years ago
  31. hubertH Group Title
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    that's it bro congrats and keep on going forwad

    • 2 years ago
  32. swin2013 Group Title
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    If they ask for acceleration and give kinetic friction is it still the same equation except it's Mu(k) - Fn = ma?

    • 2 years ago
  33. hubertH Group Title
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    no! kinetic friction is the smallest force that keeps the system moving @ constant speed

    • 2 years ago
  34. swin2013 Group Title
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    Ok...

    • 2 years ago
  35. hubertH Group Title
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    if u have more questions on science don't hesitate to massage me.....

    • 2 years ago
  36. swin2013 Group Title
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    alright because i have a big physics test and I don't really understand forces lol

    • 2 years ago
  37. hubertH Group Title
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    we'll try to make it easier together bye for now

    • 2 years ago
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