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swin2013
 3 years ago
Forces: You discover that it takes 258.0 N to set a 40.0 kg crate in motion on a concrete surface. What is the coefficient of static friction for the crate?
swin2013
 3 years ago
Forces: You discover that it takes 258.0 N to set a 40.0 kg crate in motion on a concrete surface. What is the coefficient of static friction for the crate?

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hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1@ swin u need to know what plane u are working on is it an incline plane or an horizontal plane/

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1coefficient of static friction=static frictional force/ normal rection

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1I assume the plane is horizontal: the normal reaction=weight=mg ur

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1@hubertH it doesn't say. so i assumed it was horrizontal

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1so u knw how to get to the answer right?

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1but is static friction only involved in inclined plane?

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1No.. then I wouldn't be asking lol

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1No! static friction is the force required to set the body in motion in our case it 's given as 258.0N

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1Well they're asking from the coefficient of static friction?

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1coefficient of static friction=static friction force/normal reaction

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1for horizontal plane normal reaction=mg

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1do u now have an idea of what u're doing?

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1so i say that Fnet = \[\mu _{s}  Fg = ma?\] a little do you?

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1remember u're given the Fs and the mass only

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1there is no Fa, no Fnet

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1well if it's starting to move wouldn't it be Ff = Mu(s) Fn?

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1\[mus =\frac{ ?Fmus }{Nr ? }\]

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1I have never used Nr in my FBD before?

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1Nr is ur normal reaction=mg

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1Ok so it's just normal force (Fn)

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1and since it's horizontal Fnet = 0N

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1what is Fnet standing fo?

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1The vector pointing upward

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1Ok i got it, Mu(s) = .66

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1that's it bro congrats and keep on going forwad

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1If they ask for acceleration and give kinetic friction is it still the same equation except it's Mu(k)  Fn = ma?

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1no! kinetic friction is the smallest force that keeps the system moving @ constant speed

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1if u have more questions on science don't hesitate to massage me.....

swin2013
 3 years ago
Best ResponseYou've already chosen the best response.1alright because i have a big physics test and I don't really understand forces lol

hubertH
 3 years ago
Best ResponseYou've already chosen the best response.1we'll try to make it easier together bye for now
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