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Forces: You discover that it takes 258.0 N to set a 40.0 kg crate in motion on a concrete surface. What is the coefficient of static friction for the crate?
 one year ago
 one year ago
Forces: You discover that it takes 258.0 N to set a 40.0 kg crate in motion on a concrete surface. What is the coefficient of static friction for the crate?
 one year ago
 one year ago

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hubertHBest ResponseYou've already chosen the best response.1
@ swin u need to know what plane u are working on is it an incline plane or an horizontal plane/
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
coefficient of static friction=static frictional force/ normal rection
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
I assume the plane is horizontal: the normal reaction=weight=mg ur
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
@hubertH it doesn't say. so i assumed it was horrizontal
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
so u knw how to get to the answer right?
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
but is static friction only involved in inclined plane?
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
No.. then I wouldn't be asking lol
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
No! static friction is the force required to set the body in motion in our case it 's given as 258.0N
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
Well they're asking from the coefficient of static friction?
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
coefficient of static friction=static friction force/normal reaction
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
for horizontal plane normal reaction=mg
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
dw:1351982204492:dw
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
do u now have an idea of what u're doing?
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
so i say that Fnet = \[\mu _{s}  Fg = ma?\] a little do you?
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
remember u're given the Fs and the mass only
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
there is no Fa, no Fnet
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
well if it's starting to move wouldn't it be Ff = Mu(s) Fn?
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
\[mus =\frac{ ?Fmus }{Nr ? }\]
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
I have never used Nr in my FBD before?
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
Nr is ur normal reaction=mg
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
Ok so it's just normal force (Fn)
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
and since it's horizontal Fnet = 0N
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
what is Fnet standing fo?
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
The vector pointing upward
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
Ok i got it, Mu(s) = .66
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
that's it bro congrats and keep on going forwad
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
If they ask for acceleration and give kinetic friction is it still the same equation except it's Mu(k)  Fn = ma?
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
no! kinetic friction is the smallest force that keeps the system moving @ constant speed
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
if u have more questions on science don't hesitate to massage me.....
 one year ago

swin2013Best ResponseYou've already chosen the best response.1
alright because i have a big physics test and I don't really understand forces lol
 one year ago

hubertHBest ResponseYou've already chosen the best response.1
we'll try to make it easier together bye for now
 one year ago
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