anonymous
  • anonymous
Forces: You discover that it takes 258.0 N to set a 40.0 kg crate in motion on a concrete surface. What is the coefficient of static friction for the crate?
Physics
schrodinger
  • schrodinger
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anonymous
  • anonymous
@ swin u need to know what plane u are working on is it an incline plane or an horizontal plane/
anonymous
  • anonymous
coefficient of static friction=static frictional force/ normal rection
anonymous
  • anonymous
I assume the plane is horizontal: the normal reaction=weight=mg ur

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anonymous
  • anonymous
got it buddy?
anonymous
  • anonymous
@hubertH it doesn't say. so i assumed it was horrizontal
anonymous
  • anonymous
so u knw how to get to the answer right?
anonymous
  • anonymous
but is static friction only involved in inclined plane?
anonymous
  • anonymous
No.. then I wouldn't be asking lol
anonymous
  • anonymous
No! static friction is the force required to set the body in motion in our case it 's given as 258.0N
anonymous
  • anonymous
Well they're asking from the coefficient of static friction?
anonymous
  • anonymous
coefficient of static friction=static friction force/normal reaction
anonymous
  • anonymous
for horizontal plane normal reaction=mg
anonymous
  • anonymous
|dw:1351982204492:dw|
anonymous
  • anonymous
\[mumg?\]
anonymous
  • anonymous
|dw:1351982369737:dw|
anonymous
  • anonymous
do u now have an idea of what u're doing?
anonymous
  • anonymous
so i say that Fnet = \[\mu _{s} - Fg = ma?\] a little do you?
anonymous
  • anonymous
remember u're given the Fs and the mass only
anonymous
  • anonymous
there is no Fa, no Fnet
anonymous
  • anonymous
well if it's starting to move wouldn't it be Ff = Mu(s) Fn?
anonymous
  • anonymous
\[mus =\frac{ ?Fmus }{Nr ? }\]
anonymous
  • anonymous
I have never used Nr in my FBD before?
anonymous
  • anonymous
Nr is ur normal reaction=mg
anonymous
  • anonymous
Ok so it's just normal force (Fn)
anonymous
  • anonymous
so it's Ff/Fn
anonymous
  • anonymous
exactly!
anonymous
  • anonymous
and since it's horizontal Fnet = 0N
anonymous
  • anonymous
what is Fnet standing fo?
anonymous
  • anonymous
The vector pointing upward
anonymous
  • anonymous
Ok i got it, Mu(s) = .66
anonymous
  • anonymous
that's it bro congrats and keep on going forwad
anonymous
  • anonymous
If they ask for acceleration and give kinetic friction is it still the same equation except it's Mu(k) - Fn = ma?
anonymous
  • anonymous
no! kinetic friction is the smallest force that keeps the system moving @ constant speed
anonymous
  • anonymous
Ok...
anonymous
  • anonymous
if u have more questions on science don't hesitate to massage me.....
anonymous
  • anonymous
alright because i have a big physics test and I don't really understand forces lol
anonymous
  • anonymous
we'll try to make it easier together bye for now

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