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|dw:1351976086595:dw|

|dw:1351976458012:dw|

What's the graph between? 0 to 8 or 0 to 1?

You can't use this formula in this case.

oh ok...

|dw:1351976777364:dw|
And now you can. Calculate this integral and it will be the volume.

thanks so down we... v= π (0,1) ∫(8x^2)^2 dx-(8-x)^2π?

don't*

sorry, yup i can

You can type the result and I will check it.

ok :)

64π/5?

Yes. That's correct.

Oh thanks so much!

so I just use 1 and 0 for ∫?

|dw:1351977717019:dw|

i know how i get 0 but not sure about 1, we use the graph right? cos its not between 0 and 1?

Ah ok

YEs!!!

thanks much Klim!!

No problems.