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Unam

  • 2 years ago

Find the volume of the solid obtained by rotating the region bounded by x=8 y^2, y = 1, x = 0, about the y-axis. a) 8 y^2=0, x=0, how can I solve this when its like this, I mean there's no other x values so i can use the (0, ?)∫. I'm using this V = π ∫ f(x)² dx {a,b}

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  1. Unam
    • 2 years ago
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    |dw:1351976086595:dw|

  2. klimenkov
    • 2 years ago
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    |dw:1351976458012:dw|

  3. Unam
    • 2 years ago
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    What's the graph between? 0 to 8 or 0 to 1?

  4. klimenkov
    • 2 years ago
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    You can't use this formula in this case.

  5. Unam
    • 2 years ago
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    oh ok...

  6. klimenkov
    • 2 years ago
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    |dw:1351976777364:dw| And now you can. Calculate this integral and it will be the volume.

  7. Unam
    • 2 years ago
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    thanks so down we... v= π (0,1) ∫(8x^2)^2 dx-(8-x)^2π?

  8. Unam
    • 2 years ago
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    don't*

  9. klimenkov
    • 2 years ago
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    Can't understand you, just calculate the integral I've written. And it will be the volume. Can you do this?

  10. Unam
    • 2 years ago
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    sorry, yup i can

  11. klimenkov
    • 2 years ago
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    You can type the result and I will check it.

  12. Unam
    • 2 years ago
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    ok :)

  13. Unam
    • 2 years ago
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    64π/5?

  14. klimenkov
    • 2 years ago
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    Yes. That's correct.

  15. Unam
    • 2 years ago
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    Oh thanks so much!

  16. Unam
    • 2 years ago
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    so I just use 1 and 0 for ∫?

  17. Unam
    • 2 years ago
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    |dw:1351977717019:dw|

  18. Unam
    • 2 years ago
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    i know how i get 0 but not sure about 1, we use the graph right? cos its not between 0 and 1?

  19. klimenkov
    • 2 years ago
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    You need to understand how the formula is built to get how to solve this problem. I just switch x and y, so you can use your formula.

  20. Unam
    • 2 years ago
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    Ah ok

  21. klimenkov
    • 2 years ago
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    If you will rotate the area on my second figure about x-axes you will get the volume i drew on the first figure. Got it?

  22. Unam
    • 2 years ago
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    YEs!!!

  23. Unam
    • 2 years ago
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    thanks much Klim!!

  24. klimenkov
    • 2 years ago
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    No problems.

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