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miss2ne2

  • 3 years ago

find the vertex: 4x^2-y+6=8x

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  1. .Sam.
    • 3 years ago
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    Do you know what is vertex?

  2. .Sam.
    • 3 years ago
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    A vertex can be said as corners of intersections or maximum where the line switches directions.

  3. .Sam.
    • 3 years ago
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    So to find the maximum point you have to find the maximum or minimum point. You can do this by completing the square.

  4. .Sam.
    • 3 years ago
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    4x^2-y+6=8x Arrange the equation to quadratic equation form, \[y=4 x^2-8 x+6\]

  5. .Sam.
    • 3 years ago
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    4(x^2-2x)+6 4(x-1)^2-1(4)+6 4(x-1)^2+2

  6. .Sam.
    • 3 years ago
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    4(x-1)^2+2 You can determine the coordinates from here, (x-1)=0 x=1 ------------------------------------------- y=2 So, (1,2)

  7. 03225186213
    • 3 years ago
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    formula for vertic x=-b/2a then put x in equation to find y x,y will be vertix

  8. 03225186213
    • 3 years ago
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    first arrange equ like y=ax^2+bx+constant

  9. 03225186213
    • 3 years ago
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    can you solve it now?

  10. 03225186213
    • 3 years ago
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    tell me so that i solve it for you if u dont

  11. miss2ne2
    • 3 years ago
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    i solved it

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