anonymous
  • anonymous
find the vertex: 4x^2-y+6=8x
Mathematics
chestercat
  • chestercat
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.Sam.
  • .Sam.
Do you know what is vertex?
.Sam.
  • .Sam.
A vertex can be said as corners of intersections or maximum where the line switches directions.
.Sam.
  • .Sam.
So to find the maximum point you have to find the maximum or minimum point. You can do this by completing the square.

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.Sam.
  • .Sam.
4x^2-y+6=8x Arrange the equation to quadratic equation form, \[y=4 x^2-8 x+6\]
.Sam.
  • .Sam.
4(x^2-2x)+6 4(x-1)^2-1(4)+6 4(x-1)^2+2
.Sam.
  • .Sam.
4(x-1)^2+2 You can determine the coordinates from here, (x-1)=0 x=1 ------------------------------------------- y=2 So, (1,2)
anonymous
  • anonymous
formula for vertic x=-b/2a then put x in equation to find y x,y will be vertix
anonymous
  • anonymous
first arrange equ like y=ax^2+bx+constant
anonymous
  • anonymous
can you solve it now?
anonymous
  • anonymous
tell me so that i solve it for you if u dont
anonymous
  • anonymous
i solved it

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