Here's the question you clicked on:
miss2ne2
find the vertex: 4x^2-y+6=8x
Do you know what is vertex?
A vertex can be said as corners of intersections or maximum where the line switches directions.
So to find the maximum point you have to find the maximum or minimum point. You can do this by completing the square.
4x^2-y+6=8x Arrange the equation to quadratic equation form, \[y=4 x^2-8 x+6\]
4(x^2-2x)+6 4(x-1)^2-1(4)+6 4(x-1)^2+2
4(x-1)^2+2 You can determine the coordinates from here, (x-1)=0 x=1 ------------------------------------------- y=2 So, (1,2)
formula for vertic x=-b/2a then put x in equation to find y x,y will be vertix
first arrange equ like y=ax^2+bx+constant
can you solve it now?
tell me so that i solve it for you if u dont