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kryton1212
6^(x+1)=12^(x) this equation needs to use the logarithm.
Take log for both sides, that is \[\log6^{x+1}=\log12^{x}\]Then, use log property \[logx^a = alogx\]\[(x+1)\log6=x\log12\]Can you solve it now?
yes, I can thank you:)