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kryton1212
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6^(x+1)=12^(x)
this equation needs to use the logarithm.
 one year ago
 one year ago
kryton1212 Group Title
6^(x+1)=12^(x) this equation needs to use the logarithm.
 one year ago
 one year ago

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RolyPoly Group TitleBest ResponseYou've already chosen the best response.2
Take log for both sides, that is \[\log6^{x+1}=\log12^{x}\]Then, use log property \[logx^a = alogx\]\[(x+1)\log6=x\log12\]Can you solve it now?
 one year ago

kryton1212 Group TitleBest ResponseYou've already chosen the best response.0
yes, I can thank you:)
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.2
Welcome :)
 one year ago
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