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erfan1234567

  • 3 years ago

If f(x) = 3 sin x + ln(4x), find f '(x). f '(x) =

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  1. RolyPoly
    • 3 years ago
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    f(x) = 3 sin x + ln(4x) f'(x) = d/dx (3 sin x) + d/dx (ln(4x)) d/dx sinx = cosx d/dx lnx = 1/x Can you do it now?

  2. erfan1234567
    • 3 years ago
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    3cosx+....

  3. erfan1234567
    • 3 years ago
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    :(

  4. RolyPoly
    • 3 years ago
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    d/dx ln(ax) = (1/ax) (a) = ...

  5. erfan1234567
    • 3 years ago
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    3cosx+1/x right??

  6. RolyPoly
    • 3 years ago
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    It should be!

  7. RolyPoly
    • 3 years ago
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    I meant it is correct.

  8. erfan1234567
    • 3 years ago
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    thanks

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