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anonymous
 3 years ago
cos θ = − root2 /2
anonymous
 3 years ago
cos θ = − root2 /2

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how can you get rid of the cosine?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you know the unit circle?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, so where is cos(θ) = sqrt(2/2) ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2now do u need general solution or within the range 0 to 2pi ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0these are the directionsSolve the given equation. (Enter your answers as a commaseparated list. Let k be any integer. Round terms to two decimal places where appropriate.)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2means genearalized solution, can u generalize this ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.05pi/4 ,5pi/4,3pi/4,3pi/4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0There is an infinite amount of solutions, you need to write it in a way to GENERALIZE the solution.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2so let me generalize it. cos function is periodic with 2pi. so values repeat after every 2pi*k here, \(\theta =\pm(3\pi/4+2\pi k),\pm(5\pi/4+2\pi k)\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh i see but why do u add the 2pik at the end ? because it is a periodic function?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2yes, as i said cos function is periodic with 2pi. so if a is solution, so is a+2pi, a2pi,a+4pi,a4pi, and so on

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh i see i missed this whole lesson on this section and i dont know any of it
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