anonymous
  • anonymous
cos θ = − root2 /2
Precalculus
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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baldymcgee6
  • baldymcgee6
how can you get rid of the cosine?
anonymous
  • anonymous
arc cos?
baldymcgee6
  • baldymcgee6
yep

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baldymcgee6
  • baldymcgee6
do you know the unit circle?
anonymous
  • anonymous
yup
baldymcgee6
  • baldymcgee6
okay, so where is cos(θ) = -sqrt(2/2) ?
anonymous
  • anonymous
3pi/4
baldymcgee6
  • baldymcgee6
Yes.. correct.
hartnn
  • hartnn
what about 5pi/4 ?
hartnn
  • hartnn
now do u need general solution or within the range 0 to 2pi ?
anonymous
  • anonymous
these are the directionsSolve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places where appropriate.)
hartnn
  • hartnn
means genearalized solution, can u generalize this ?
anonymous
  • anonymous
5pi/4 ,-5pi/4,3pi/4,-3pi/4
baldymcgee6
  • baldymcgee6
There is an infinite amount of solutions, you need to write it in a way to GENERALIZE the solution.
hartnn
  • hartnn
so let me generalize it. cos function is periodic with 2pi. so values repeat after every 2pi*k here, \(\theta =\pm(3\pi/4+2\pi k),\pm(5\pi/4+2\pi k)\)
anonymous
  • anonymous
ohh i see but why do u add the 2pik at the end ? because it is a periodic function?
hartnn
  • hartnn
yes, as i said cos function is periodic with 2pi. so if a is solution, so is a+2pi, a-2pi,a+4pi,a-4pi, and so on
anonymous
  • anonymous
ohh i see i missed this whole lesson on this section and i dont know any of it

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