I don't get it. How would I solve it

- anonymous

I don't get it. How would I solve it

- chestercat

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- anonymous

##### 1 Attachment

- anonymous

before u can graph this equation get the equation in standard form: y=mx+b

- mayankdevnani

first solve this equation
y-3=2(x-4)
y-3=2x-8
y=2x-5

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## More answers

- anonymous

I got 2x-5, I'm having trouble graphing...

- mayankdevnani

@SephI now solve it

- mayankdevnani

put the value of x=0
y=0-5=-5

- mayankdevnani

1solution=(0,-5)

- anonymous

b is the y intercept

- mayankdevnani

put the value of x=1
y=2-5
y=-3

- mayankdevnani

2 solution=(1,-3)

- mayankdevnani

@SephI there are may solutions

- mayankdevnani

got it @SephI

- anonymous

so -5 is the y value when x is 0
then the slope is m which is 2
so go up 2 points from -5 go left 1 because your slope is really 2/1
that's you next point then draw a line through both points

- anonymous

No, no I don't. Putting different numbers in will give me different answers?

- mayankdevnani

then you will get a straight line

- mayankdevnani

am i wrong?
@Bhagyashree

- anonymous

Okay, walk through step-by-step

- mayankdevnani

you don't understand

- anonymous

you are not wrong @mayankdevnani it is just a different method

- mayankdevnani

oh!! but it is right @SephI

- anonymous

wait let me explain in a different way

- mayankdevnani

uw you can

- mayankdevnani

there are infinitely solutions @SephI

- anonymous

Ok

- anonymous

@mayankdevnani , go on...

- anonymous

as what @mayankdevnani just said is right
if u plug a value of x in an equation u get a value of y for that x value
if u get 2 of those points they both belong to one equation that u want to graph
so its not wrong
u can also look at previous answer which is a different method of graphing

- mayankdevnani

now put the value of x=5
y=10-5=5

- mayankdevnani

2solution=(5,5)

- mayankdevnani

now you understand @SephI

- mayankdevnani

take the value of x=4
y=8-5=3

- mayankdevnani

3solution=(4,3)

- mayankdevnani

also (4,3) is in the graph as line pass through it

- mayankdevnani

ok @SephI

- mayankdevnani

@hartnn am i right?

- hartnn

about what ?
u have to graph the line, right ?
find x and y intercepts, plot them, and just daw a staright line passing through them.
To get x-intercept put y=0 in the equation
to get y-intercept put x=0 in the equation
i am too lazy to go through all the comments....

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