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before u can graph this equation get the equation in standard form: y=mx+b
first solve this equation y-3=2(x-4) y-3=2x-8 y=2x-5
I got 2x-5, I'm having trouble graphing...
@SephI now solve it
put the value of x=0 y=0-5=-5
b is the y intercept
put the value of x=1 y=2-5 y=-3
@SephI there are may solutions
got it @SephI
so -5 is the y value when x is 0 then the slope is m which is 2 so go up 2 points from -5 go left 1 because your slope is really 2/1 that's you next point then draw a line through both points
No, no I don't. Putting different numbers in will give me different answers?
then you will get a straight line
am i wrong? @Bhagyashree
Okay, walk through step-by-step
you don't understand
you are not wrong @mayankdevnani it is just a different method
oh!! but it is right @SephI
wait let me explain in a different way
uw you can
there are infinitely solutions @SephI
@mayankdevnani , go on...
as what @mayankdevnani just said is right if u plug a value of x in an equation u get a value of y for that x value if u get 2 of those points they both belong to one equation that u want to graph so its not wrong u can also look at previous answer which is a different method of graphing
now put the value of x=5 y=10-5=5
now you understand @SephI
take the value of x=4 y=8-5=3
also (4,3) is in the graph as line pass through it
@hartnn am i right?
about what ? u have to graph the line, right ? find x and y intercepts, plot them, and just daw a staright line passing through them. To get x-intercept put y=0 in the equation to get y-intercept put x=0 in the equation i am too lazy to go through all the comments....