rva.raghav
Disssolving 120g of urea(mol wt 60)in 1000g of water gave a sol of density 1.15g/ml.the molarity of the solution is ....? please tell me detailed steps.
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rva.raghav
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Please tell me soon
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Do u knw wat is Molarity..?
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\[D=\frac{ M }{ V }\]
\[V=\frac{ M }{ D }\]
M = 1000 + 120 = 1120gm
rva.raghav
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but the answer is 2.05M
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Lol....First Find V
then use Molarity = no of moles of solute / Volume (L)
rva.raghav
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how to find V
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hm..thats wat i have Given u.....)
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1.15 g/ml = 1150 g/L
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\[V = 1120/1150 = 0.973L\]
no of moles = 120/60 = 2
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\[M = 2/0.973 = 2.05M\]
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hope u got it...)
rva.raghav
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tks
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Welcome..)
rva.raghav
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yahoo...yahooo......oooooooooooooooo..............
rva.raghav
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please wait i have to ask u another question
rva.raghav
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Why NPN transistors a more preferred than PNP?