A community for students.
Here's the question you clicked on:
 0 viewing
rva.raghav
 4 years ago
Disssolving 120g of urea(mol wt 60)in 1000g of water gave a sol of density 1.15g/ml.the molarity of the solution is ....? please tell me detailed steps.
rva.raghav
 4 years ago
Disssolving 120g of urea(mol wt 60)in 1000g of water gave a sol of density 1.15g/ml.the molarity of the solution is ....? please tell me detailed steps.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do u knw wat is Molarity..?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[D=\frac{ M }{ V }\] \[V=\frac{ M }{ D }\] M = 1000 + 120 = 1120gm

rva.raghav
 4 years ago
Best ResponseYou've already chosen the best response.0but the answer is 2.05M

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Lol....First Find V then use Molarity = no of moles of solute / Volume (L)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hm..thats wat i have Given u.....)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[V = 1120/1150 = 0.973L\] no of moles = 120/60 = 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[M = 2/0.973 = 2.05M\]

rva.raghav
 4 years ago
Best ResponseYou've already chosen the best response.0yahoo...yahooo......oooooooooooooooo..............

rva.raghav
 4 years ago
Best ResponseYou've already chosen the best response.0please wait i have to ask u another question

rva.raghav
 4 years ago
Best ResponseYou've already chosen the best response.0Why NPN transistors a more preferred than PNP?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.