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\[\cot=1/\tan\]
\[\tan=sin/cos\]
\[sec=1/cos \]

Ok, can you explain further?

Use the first 2 equations to get \[cot=cos/sin \]

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Ok

So is it cos/sin times 1/cosx times 1/cscx ???

Ok so it's csc^2x

\[\frac{\cos}{\sin}\sin \frac{1}{\cos}=1\]

Sorry for my last post, I forgot it was sin.
No, it's 1 I think

Oh

cot θ sec θ sin θ
(cos θ/sin θ) (1/cos θ) sin θ

Oh ok got it, thanks so much :)

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