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angela210793 Group TitleBest ResponseYou've already chosen the best response.2
dw:1352048933dw:1352048968202:dw095:dw
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
? Is \(\large k^3 (\frac{k^7}{5})^{5}\) ?
 one year ago

angela210793 Group TitleBest ResponseYou've already chosen the best response.2
:O where did my solution go :O
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
^ ? I dunno, looks like you were trying to post a drawing.
 one year ago

JessicaNicoleCraven Group TitleBest ResponseYou've already chosen the best response.0
I am so confused. Its suppose to be k with an exponent of 3, times k(7/5) with an exponent of negative 5.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
Then is it \(\large k^3 \cdot (k^{7/5})^{5} \) ?
 one year ago

JessicaNicoleCraven Group TitleBest ResponseYou've already chosen the best response.0
Yeah.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
Ok. Order of operations, handle the exponent first. A powertoapower, multiply the exponents.
 one year ago

angela210793 Group TitleBest ResponseYou've already chosen the best response.2
All u have to know is that x^a*x^b=x^(a+b) (x^a)^b=x^ab and x^a=1/x^a so u'll have dw:1352049321095:dw
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
\(\huge \rightarrow k^3 \cdot k^{(\frac{7}{5} \cdot 5)} \) \(\huge \rightarrow k^3 \cdot k^{7}\)
 one year ago

JessicaNicoleCraven Group TitleBest ResponseYou've already chosen the best response.0
Oh wow, thats a lot more simple than I was trying to make it. Thank you!
 one year ago
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