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JessicaNicoleCraven
 3 years ago
k^3(k7/5)^5
JessicaNicoleCraven
 3 years ago
k^3(k7/5)^5

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angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1352048933dw:1352048968202:dw095:dw

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0? Is \(\large k^3 (\frac{k^7}{5})^{5}\) ?

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2:O where did my solution go :O

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0^ ? I dunno, looks like you were trying to post a drawing.

JessicaNicoleCraven
 3 years ago
Best ResponseYou've already chosen the best response.0I am so confused. Its suppose to be k with an exponent of 3, times k(7/5) with an exponent of negative 5.

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0Then is it \(\large k^3 \cdot (k^{7/5})^{5} \) ?

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0Ok. Order of operations, handle the exponent first. A powertoapower, multiply the exponents.

angela210793
 3 years ago
Best ResponseYou've already chosen the best response.2All u have to know is that x^a*x^b=x^(a+b) (x^a)^b=x^ab and x^a=1/x^a so u'll have dw:1352049321095:dw

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0\(\huge \rightarrow k^3 \cdot k^{(\frac{7}{5} \cdot 5)} \) \(\huge \rightarrow k^3 \cdot k^{7}\)

JessicaNicoleCraven
 3 years ago
Best ResponseYou've already chosen the best response.0Oh wow, thats a lot more simple than I was trying to make it. Thank you!
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