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angela210793 Group TitleBest ResponseYou've already chosen the best response.2
dw:1352048933dw:1352048968202:dw095:dw
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
? Is \(\large k^3 (\frac{k^7}{5})^{5}\) ?
 2 years ago

angela210793 Group TitleBest ResponseYou've already chosen the best response.2
:O where did my solution go :O
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
^ ? I dunno, looks like you were trying to post a drawing.
 2 years ago

JessicaNicoleCraven Group TitleBest ResponseYou've already chosen the best response.0
I am so confused. Its suppose to be k with an exponent of 3, times k(7/5) with an exponent of negative 5.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
Then is it \(\large k^3 \cdot (k^{7/5})^{5} \) ?
 2 years ago

JessicaNicoleCraven Group TitleBest ResponseYou've already chosen the best response.0
Yeah.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
Ok. Order of operations, handle the exponent first. A powertoapower, multiply the exponents.
 2 years ago

angela210793 Group TitleBest ResponseYou've already chosen the best response.2
All u have to know is that x^a*x^b=x^(a+b) (x^a)^b=x^ab and x^a=1/x^a so u'll have dw:1352049321095:dw
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
\(\huge \rightarrow k^3 \cdot k^{(\frac{7}{5} \cdot 5)} \) \(\huge \rightarrow k^3 \cdot k^{7}\)
 2 years ago

JessicaNicoleCraven Group TitleBest ResponseYou've already chosen the best response.0
Oh wow, thats a lot more simple than I was trying to make it. Thank you!
 2 years ago
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