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perpendicular bisector of BC

sure

Sure. You are welcome.

|dw:1352049851819:dw|

do u know how to solve this algebraically ?

how to get to 'perpendicular bisector of BC'

Emmm, i don't think so.. like what do you mean? show me? :)

|dw:1352049933632:dw|

Does it matter?

Yea..the point A can be above BC or below BC according to that figure

Okay, thank youu!

welcome :-)

|dw:1352050205624:dw|

Oh, oh! No.. not yet at least. Let me know how to find the locus first :P Thank you though!!

Ok got it..that isn't the correction..the correction is B=(a,0)

correction is in diagram! not there |dw:1352050580220:dw|

Ya ya..that's what I was talking about

Yes I did! So you can get it with solving.. Not by memorizing the conditions or cases. Nice!

always!