henpen
\[ \int \frac{x}{x^2+1}dx \]



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phi
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this (almost) looks like u^1 du

henpen
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This smells of parts, but I'm having trouble with \[\int\limits \frac{1}{x^2+1}dx\]

sirm3d
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that is arctangent

henpen
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Although that might not help

sirm3d
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can you enlighten us with the problem?

klimenkov
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Do a substitution \(u=x^2, du=2xdx\)

henpen
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\[0.5 \ln(u+1)\]

henpen
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@sirm3d It's halfway through the DE of my last question

klimenkov
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Yes. Now make the inverse substitution.

sirm3d
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post a link @henpen


sirm3d
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hmm, can we try reduction of order with \[y=v(ix)\]