anonymous
  • anonymous
Assuming R is right isocele triangle, I have to find the polar moment of inertia about its right-angle vertex, how is this thing turning? (Ref. Supplementary problems PS7 ex 3c-1)
OCW Scholar - Multivariable Calculus
chestercat
  • chestercat
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anonymous
  • anonymous
Came across this definition on Wikipedia; hope this helps: If a mechanical system is constrained to move parallel to a fixed plane, then the rotation of a body in the system occurs around an axis k perpendicular to this plane. In this case, the moment of inertia of the mass in this system is a scalar known as the polar moment of inertia. Imagine the triangle turning in the xy-plane, with the right angle vertex as the pivot.
anonymous
  • anonymous
Poojat is correct. Think of it as spinning while the right-angle vertex is pinned. CW or CCW spin makes no difference.

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