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Assuming R is right isocele triangle, I have to find the polar moment of inertia about its rightangle vertex, how is this thing turning? (Ref. Supplementary problems PS7 ex 3c1)
 one year ago
 one year ago
Assuming R is right isocele triangle, I have to find the polar moment of inertia about its rightangle vertex, how is this thing turning? (Ref. Supplementary problems PS7 ex 3c1)
 one year ago
 one year ago

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poojatBest ResponseYou've already chosen the best response.0
Came across this definition on Wikipedia; hope this helps: If a mechanical system is constrained to move parallel to a fixed plane, then the rotation of a body in the system occurs around an axis k perpendicular to this plane. In this case, the moment of inertia of the mass in this system is a scalar known as the polar moment of inertia. Imagine the triangle turning in the xyplane, with the right angle vertex as the pivot.
 one year ago

senecajimBest ResponseYou've already chosen the best response.0
Poojat is correct. Think of it as spinning while the rightangle vertex is pinned. CW or CCW spin makes no difference.
 one year ago
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