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anonymous
 3 years ago
Assuming R is right isocele triangle, I have to find the polar moment of inertia about its rightangle vertex, how is this thing turning? (Ref. Supplementary problems PS7 ex 3c1)
anonymous
 3 years ago
Assuming R is right isocele triangle, I have to find the polar moment of inertia about its rightangle vertex, how is this thing turning? (Ref. Supplementary problems PS7 ex 3c1)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Came across this definition on Wikipedia; hope this helps: If a mechanical system is constrained to move parallel to a fixed plane, then the rotation of a body in the system occurs around an axis k perpendicular to this plane. In this case, the moment of inertia of the mass in this system is a scalar known as the polar moment of inertia. Imagine the triangle turning in the xyplane, with the right angle vertex as the pivot.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Poojat is correct. Think of it as spinning while the rightangle vertex is pinned. CW or CCW spin makes no difference.
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