A community for students.
Here's the question you clicked on:
 0 viewing
ksaimouli
 3 years ago
a conical pendulum is formed by attaching a 50g mass to a 1.2m string. The mass swings around the circle of radius 25cm (a) calculate the speed of the mass
ksaimouli
 3 years ago
a conical pendulum is formed by attaching a 50g mass to a 1.2m string. The mass swings around the circle of radius 25cm (a) calculate the speed of the mass

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352058857282:dw Where does the 0.25m circle come into this? I don't quite get the question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352059091446:dw\[T_y=mg\]

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1352059120155:dw

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2after that i dont get

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Using MY angle theta (so I can copy/paste pictures easier later), \[0.05g=Tsin(\theta)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352059242987:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0As it does not move up or down

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2what is the equation actually

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you get why the equality is correct?

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1352059579894:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[T_ymg=0\]I think, as the NET force in the vertical axis is 0, as it doesn't move up or down.

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2it is circular motion so that must be= mv^2/r

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0In the horizontal axis yes, but we are resolving in the verical axis nowdw:1352059672600:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[T=\frac{0.05 *9.8}{\sin78}\approx0.5 N\] \[T_x=Tcos(\theta)=0.5\cos(78)\approx0.1N\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[T_x=\frac{mv^2}{r}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[v=\sqrt{\frac{0.1*0.25}{0.05}} \approx 0.7 m/s\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352059964786:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes I know that centrifugal is fictitious, but it's required if you want to use Newton's Laws in rotating systems. http://xkcd.com/123/

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2now i will explain my method can u correct me

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1352060338398:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[0.05*9.8/\cos12=0.5\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Calculator error it seems

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You need to provide dimensions along with your numbers.

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2where did the .1 came from

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2i got .5N for tension

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2why did u find that one

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.2because horizontal force?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0T=0.5 I got when resolving vertically\[Tsin \theta=mg\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352061108396:dw
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.