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pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Find an equation of the form y = sin(xp) whose graph passes through.... (pi/6,0)
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Pleaseeee help me ~~
 one year ago

zonazoo Group TitleBest ResponseYou've already chosen the best response.1
well i know what it is asking, i just cant seem to think how to do it... all it wants you to do is change the parameters so that the x intercept is pi/6.... so to me all you are doing is shifting the graph to the right pi/6 units, the sine function starts off at the origin (0,0), but they want it to go through (pi/6, 0) so just move it to the right that many units..
 one year ago

zonazoo Group TitleBest ResponseYou've already chosen the best response.1
all i would think is that the new equation is y=sin(x(pi/6))
 one year ago

zonazoo Group TitleBest ResponseYou've already chosen the best response.1
because, i believe that p value is the one that will shift the function left and right.
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Thank you!
 one year ago

zonazoo Group TitleBest ResponseYou've already chosen the best response.1
did that make sense?
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Yeah, let me just think about it a little more. Your answer makes sense
 one year ago

zonazoo Group TitleBest ResponseYou've already chosen the best response.1
if you think about all the sine functions in a form of y=a + bsin(k(xc) the a will change your graph up and down the b will make it taller or shorter the k will make it wider or skinner the c will make it move right or left so in this case since you only have y=sin(xp), the only paramater that you can change is the p value, or c in my example, which just moves it left or right, so if you put that value in, pi/6, you should get the graph there.
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
I get it now :)) Thanks for your time
 one year ago

zonazoo Group TitleBest ResponseYou've already chosen the best response.1
you are welcome.
 one year ago
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