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pottersheep

  • 2 years ago

Advanced Functions - TRIG help please!

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  1. pottersheep
    • 2 years ago
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    Find an equation of the form y = sin(x-p) whose graph passes through.... (pi/6,0)

  2. pottersheep
    • 2 years ago
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    Pleaseeee help me ~~

  3. zonazoo
    • 2 years ago
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    well i know what it is asking, i just cant seem to think how to do it... all it wants you to do is change the parameters so that the x intercept is pi/6.... so to me all you are doing is shifting the graph to the right pi/6 units, the sine function starts off at the origin (0,0), but they want it to go through (pi/6, 0) so just move it to the right that many units..

  4. zonazoo
    • 2 years ago
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    all i would think is that the new equation is y=sin(x-(pi/6))

  5. zonazoo
    • 2 years ago
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    because, i believe that p value is the one that will shift the function left and right.

  6. pottersheep
    • 2 years ago
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    Thank you!

  7. zonazoo
    • 2 years ago
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    did that make sense?

  8. pottersheep
    • 2 years ago
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    Yeah, let me just think about it a little more. Your answer makes sense

  9. zonazoo
    • 2 years ago
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    if you think about all the sine functions in a form of y=a + bsin(k(x-c) the a will change your graph up and down the b will make it taller or shorter the k will make it wider or skinner the c will make it move right or left so in this case since you only have y=sin(x-p), the only paramater that you can change is the p value, or c in my example, which just moves it left or right, so if you put that value in, pi/6, you should get the graph there.

  10. pottersheep
    • 2 years ago
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    True!

  11. pottersheep
    • 2 years ago
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    I get it now :)) Thanks for your time

  12. zonazoo
    • 2 years ago
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    you are welcome.

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