1. pottersheep

Find an equation of the form y = sin(x-p) whose graph passes through.... (pi/6,0)

2. pottersheep

3. zonazoo

well i know what it is asking, i just cant seem to think how to do it... all it wants you to do is change the parameters so that the x intercept is pi/6.... so to me all you are doing is shifting the graph to the right pi/6 units, the sine function starts off at the origin (0,0), but they want it to go through (pi/6, 0) so just move it to the right that many units..

4. zonazoo

all i would think is that the new equation is y=sin(x-(pi/6))

5. zonazoo

because, i believe that p value is the one that will shift the function left and right.

6. pottersheep

Thank you!

7. zonazoo

did that make sense?

8. pottersheep

9. zonazoo

if you think about all the sine functions in a form of y=a + bsin(k(x-c) the a will change your graph up and down the b will make it taller or shorter the k will make it wider or skinner the c will make it move right or left so in this case since you only have y=sin(x-p), the only paramater that you can change is the p value, or c in my example, which just moves it left or right, so if you put that value in, pi/6, you should get the graph there.

10. pottersheep

True!

11. pottersheep

I get it now :)) Thanks for your time

12. zonazoo

you are welcome.