At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

|dw:1352072429317:dw|

t >=0

what i did is for velocity =0 to find the critical points

|dw:1352072565266:dw|

so from (-inf,2) left and (2,inft) right

is this right

no, it's a particle that's moving left initially, and accelerating to the right...

Vi =-4
a=2

so how to approach it then

you're right that it has V=0 at t=2, but other than that, I'm not sure what your trying to say.

that's it.

i dont know how they got it

you left something out then, there's nothing about position in your statement.

what's that second line supposed to be? I guessed it was a=2...

is it supposed to be d(0)=2 or something?

|dw:1352073305950:dw|

this was the question

...

when t=0 x=3

when V= 0, t=2 and x=?