## ksaimouli 3 years ago describe the motion of the particle

1. ksaimouli

|dw:1352072429317:dw|

2. ksaimouli

t >=0

3. ksaimouli

@zepdrix

4. ksaimouli

what i did is for velocity =0 to find the critical points

5. ksaimouli

|dw:1352072565266:dw|

6. ksaimouli

so from (-inf,2) left and (2,inft) right

7. ksaimouli

is this right

8. Algebraic!

no, it's a particle that's moving left initially, and accelerating to the right...

9. Algebraic!

Vi =-4 a=2

10. ksaimouli

so how to approach it then

11. Algebraic!

you're right that it has V=0 at t=2, but other than that, I'm not sure what your trying to say.

12. Algebraic!

that's it.

13. Algebraic!

initially moving left, accelerating right, 'turning around' at t=2, then heading right (and accelerating) forever.

14. ksaimouli

the answer is it begins at a position 3 moving in a negative direction.it moves to position -1 when t=2 and then changes direction moving in a positive direction thereafter

15. ksaimouli

i dont know how they got it

16. ksaimouli

@Algebraic!

17. Algebraic!

you left something out then, there's nothing about position in your statement.

18. Algebraic!

what's that second line supposed to be? I guessed it was a=2...

19. Algebraic!

is it supposed to be d(0)=2 or something?

20. ksaimouli

a particle is moving along the x axis with position functionx(t) find the (a) velocity (b) acceleration (c)describe the motion of the particle at t>=0

21. ksaimouli

|dw:1352073305950:dw|

22. ksaimouli

this was the question

23. Algebraic!

...

24. Algebraic!

when t=0 x=3

25. Algebraic!

when V= 0, t=2 and x=?