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neom15

  • 2 years ago

The source in the circuit below has a voltage trace given by vs(t) = 19cos(1005t). The resistance is 55 Ω, the inductance is 150 mH, and the capacitance is 9.7 μF. What load resistance should be connected to the two terminals to allow maximum power transfer?

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  1. Varuns
    • 2 years ago
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    Well, you have to first find XL and Xc, the inductive and capacitive reactances. And then calculate R, the load resistance as \[\sqrt{R ^{2}+ (XL-Xc)^{2}}\]

  2. ghazi
    • 2 years ago
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    for maximum power transfer it should be complex conjugate of thevnin's impedance

  3. ghazi
    • 2 years ago
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    |dw:1352173597489:dw| to find thevnin's impedance short the voltage source and calculate the impedance to find frequency use standard equation and make comparision

  4. ghazi
    • 2 years ago
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    \[V(t)= A \sin (w t)\] w= 1005 and Rth = \[\sqrt {R^2+(X _{l})^2-X^2 _{c}}\] \[X _{l}= 2* \pi * f * L-------X _{c}=\frac{ 1 }{ 2 \pi f c }\] use this solve the complex part and if there is no complex part than your load resistance should be equal to your internal impedance for the maximum power transfer

  5. knowelectronics
    • 2 years ago
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    First find the equivalent thevenin circuit.Then replace the internal resistance by thevenins resistance.Maximum power is transferred when internal resistance and load resistance are equal.For more visit www.knowelectronics.org

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