Gungirl4ever1994
identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)2 – 3. (1 point)vertex: (2, –3); axis of symmetry: x = 2
vertex: (–2, –3); axis of symmetry: x = –2
vertex: (2, 3); axis of symmetry: x = 2
vertex: (–2, 3); axis of symmetry: x = –2
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Gungirl4ever1994
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@ghazi
ghazi
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have you tried to plot it?
Gungirl4ever1994
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idk what it even is ghazi
ghazi
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y=3x+6-3=3x+3 is this clear?
Gungirl4ever1994
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combine like terms?
ghazi
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yes, now lets say we have to find value of y at different values of X
Gungirl4ever1994
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well y = 3x+3=3x-+3
ghazi
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y=3x+3, now when x=0,y=3 and when x=-1, y=0 we use this to plot a graph
ghazi
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wait what is your function it looks like parabola?
ghazi
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\[y=(3x+2)^2-3\] is this your function?
Gungirl4ever1994
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no wait the 3 is outside the ()
ghazi
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\[y=3(x+2)^2-3\] this one