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Gungirl4ever1994

  • 3 years ago

identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)2 – 3. (1 point)vertex: (2, –3); axis of symmetry: x = 2 vertex: (–2, –3); axis of symmetry: x = –2 vertex: (2, 3); axis of symmetry: x = 2 vertex: (–2, 3); axis of symmetry: x = –2

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  1. Gungirl4ever1994
    • 3 years ago
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    @ghazi

  2. ghazi
    • 3 years ago
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    have you tried to plot it?

  3. Gungirl4ever1994
    • 3 years ago
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    idk what it even is ghazi

  4. ghazi
    • 3 years ago
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    y=3x+6-3=3x+3 is this clear?

  5. Gungirl4ever1994
    • 3 years ago
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    combine like terms?

  6. ghazi
    • 3 years ago
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    yes, now lets say we have to find value of y at different values of X

  7. Gungirl4ever1994
    • 3 years ago
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    well y = 3x+3=3x-+3

  8. ghazi
    • 3 years ago
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    y=3x+3, now when x=0,y=3 and when x=-1, y=0 we use this to plot a graph

  9. ghazi
    • 3 years ago
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    wait what is your function it looks like parabola?

  10. Gungirl4ever1994
    • 3 years ago
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    huh?

  11. ghazi
    • 3 years ago
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    \[y=(3x+2)^2-3\] is this your function?

  12. Gungirl4ever1994
    • 3 years ago
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    yes

  13. Gungirl4ever1994
    • 3 years ago
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    no wait the 3 is outside the ()

  14. ghazi
    • 3 years ago
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    \[y=3(x+2)^2-3\] this one

  15. Gungirl4ever1994
    • 3 years ago
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    yes

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