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anonymous
 4 years ago
Starting with the data values 70 and 100, add three data values to the sample so that the mean is 86, the median is 82, and the mode is 82. Please show all of your work.
anonymous
 4 years ago
Starting with the data values 70 and 100, add three data values to the sample so that the mean is 86, the median is 82, and the mode is 82. Please show all of your work.

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lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1have you tried trial and error?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes it just confuses me a bit more

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1actually....it's not much of "error"... you know the start is 70 and the last is 100...then there are three blanks in the middle 70 _ _ _ 100 right?

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1then it says the median is 82...so what do you think should you do?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0theoretically, it should look something like 70+82+82+x+100/5= 66.8

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1except... it says the mean is 86 so it should be (72 + 82 + 82 + x + 100)/5 = 86

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh. So, then how do you find that x?

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1that should be \[\frac{70 + 82 + 82 + x + 100}5 = 86\]

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1to solve for x, you should multiply both sides by 5 first

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so have 5*86, which comes to 430, and I believe we can subtract the original 334 by 430, right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0awesome. That missing number would come to be 96. Thank you!
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