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hey its too much easy... |f(x)|=sqrt((1)^2+(1)^2)=sqrt(2)

The question is right. I know DeMoivres, but in this case it's sin(x) + icos(x).

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ah oookkk ya its absolute value

no i is denominator from demorvie`s, but in this case I did`nt get u how u got this result

ok am gonna solve its prove and implement according to this condition the `ll msg u here ok

Thanks :) I'm so confused...

hahahhah i just wanna say write i in denominator ok i mean (eix−e−ix)2+(eix+e−ix)2i

Hmm... I don't get it. How does that show that |sin(x) + icos(x)| = 1?

oh i see wait i solve it and post the diagrame okk buddy

Anyone?

pdf attached here.

u got ur answer or not /??

Nope, heh. Not yet :(

ok if its difficault then msg me ur question i will solve it my self and will post the pic here
ok

Yeah I don't know how to get the function to = 1...

You're welcome! :)

perhaps this definition can refresh you \[\huge \left| a + bi \right|=a^2+b^2 \]

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