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odehye

Graph X^2 + (y +3)^2=9

  • one year ago
  • one year ago

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  1. AccessDenied
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    Are you familiar with what sort of shape you'll get from an equation of this form?

    • one year ago
  2. odehye
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    Not this one

    • one year ago
  3. AccessDenied
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    Okay. Equations of the form \((x - h)^2 + (y - k )^2 = r^2\) are considered circles. The center of the circle is (h, k), and the radius is r. So, you can usually make comparisons between the 'standard form'and the given equation to figure out your center + radius, and graph from that. :)

    • one year ago
  4. odehye
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    will the center b (0,-3)?

    • one year ago
  5. AccessDenied
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    Yes, that is correct.

    • one year ago
  6. odehye
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    So then this will be a circle intersecting at ±3 all round

    • one year ago
  7. AccessDenied
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    Hmm... well, the circle simply has a radius of three, so basically all the points that are a distance of 3 from (0, -3) are points on your graph. It makes sense if you consider r the distance between the center and all the points on the circle that are 3 units away. :)

    • one year ago
  8. odehye
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    |dw:1352106893652:dw|

    • one year ago
  9. AccessDenied
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    The exact center of the circle will be at (0, -3), like this: |dw:1352107269477:dw|

    • one year ago
  10. odehye
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    Since the radius is 9 and the √9=3

    • one year ago
  11. AccessDenied
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    Our radius is determined as r^2 = 9 => r = 3. :) So, we can draw in all the points around (0, -3) that are a distance of 3 units away for the circle.

    • one year ago
  12. AccessDenied
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    |dw:1352107502707:dw| So, we can pick out a few simple ones that line up on the axes, and then we have to estimate from there. My graph isn't drawn particularly well, so it doesn't look very nice, but you should be able to get a circle. :P

    • one year ago
  13. odehye
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    So the points are (0,0) (3,-3) (0,-6) (-3,-3)?

    • one year ago
  14. AccessDenied
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    Yes, those are a few points on the graph of the circle. If you start from your center, it is easiest to move horizontally or vertically by the same distance as the radius to find four points to draw the rest of the graph from.

    • one year ago
  15. AccessDenied
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    The process of graphing the circle basically goes like this: 1) Find your center-point and radius 2) Plot the center-point on your graph 3) Plot those four points at a distance of one radius away and draw in the circle from there as best you can. Usually teachers will be forgiving as long as you have those four points marked and your circle looks somewhere close. :P

    • one year ago
  16. odehye
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    You've been so much helpful

    • one year ago
  17. odehye
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    I have about 6 more qtns to go. I'm staying awake till class time which is 7am

    • one year ago
  18. AccessDenied
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    I'm glad to be able to help! :) Although, I will have to get off. I should really be sleeping...

    • one year ago
  19. odehye
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    Sure. Thank a million.

    • one year ago
  20. odehye
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    Good night and sound sleep.

    • one year ago
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