anonymous
  • anonymous
Graph X^2 + (y +3)^2=9
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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AccessDenied
  • AccessDenied
Are you familiar with what sort of shape you'll get from an equation of this form?
anonymous
  • anonymous
Not this one
AccessDenied
  • AccessDenied
Okay. Equations of the form \((x - h)^2 + (y - k )^2 = r^2\) are considered circles. The center of the circle is (h, k), and the radius is r. So, you can usually make comparisons between the 'standard form'and the given equation to figure out your center + radius, and graph from that. :)

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anonymous
  • anonymous
will the center b (0,-3)?
AccessDenied
  • AccessDenied
Yes, that is correct.
anonymous
  • anonymous
So then this will be a circle intersecting at ±3 all round
AccessDenied
  • AccessDenied
Hmm... well, the circle simply has a radius of three, so basically all the points that are a distance of 3 from (0, -3) are points on your graph. It makes sense if you consider r the distance between the center and all the points on the circle that are 3 units away. :)
anonymous
  • anonymous
|dw:1352106893652:dw|
AccessDenied
  • AccessDenied
The exact center of the circle will be at (0, -3), like this: |dw:1352107269477:dw|
anonymous
  • anonymous
Since the radius is 9 and the √9=3
AccessDenied
  • AccessDenied
Our radius is determined as r^2 = 9 => r = 3. :) So, we can draw in all the points around (0, -3) that are a distance of 3 units away for the circle.
AccessDenied
  • AccessDenied
|dw:1352107502707:dw| So, we can pick out a few simple ones that line up on the axes, and then we have to estimate from there. My graph isn't drawn particularly well, so it doesn't look very nice, but you should be able to get a circle. :P
anonymous
  • anonymous
So the points are (0,0) (3,-3) (0,-6) (-3,-3)?
AccessDenied
  • AccessDenied
Yes, those are a few points on the graph of the circle. If you start from your center, it is easiest to move horizontally or vertically by the same distance as the radius to find four points to draw the rest of the graph from.
AccessDenied
  • AccessDenied
The process of graphing the circle basically goes like this: 1) Find your center-point and radius 2) Plot the center-point on your graph 3) Plot those four points at a distance of one radius away and draw in the circle from there as best you can. Usually teachers will be forgiving as long as you have those four points marked and your circle looks somewhere close. :P
anonymous
  • anonymous
You've been so much helpful
anonymous
  • anonymous
I have about 6 more qtns to go. I'm staying awake till class time which is 7am
AccessDenied
  • AccessDenied
I'm glad to be able to help! :) Although, I will have to get off. I should really be sleeping...
anonymous
  • anonymous
Sure. Thank a million.
anonymous
  • anonymous
Good night and sound sleep.

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