rva.raghav
  • rva.raghav
At noon on a sunny day, there is a solar irradiance of 1 kW/m2 impinging on a solar panel that is 1 meter by 1.6 meters. To simplify the problem we assume here that the light is all the same wavelength λ=732 nm.Determine the number of photons per second incident on the panel.
Physics
katieb
  • katieb
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ujjwal
  • ujjwal
The area of solar panel is 1.6 \(m^2\). The energy of photons striking 1 \(m^2\) per sec is 1000 J So, the energy of photons striking 1.6 \(m^2\) per sec is 1.6 \(\times\)1000=1600 J Now you need to find the number of photons which will have energy of 1600 J let that number be n So,\[nh\frac{c}{\lambda}=1600\]where h is plank's constant and c is velocity of light you have \(\lambda\). Find n
rva.raghav
  • rva.raghav
thks ujjwal
ujjwal
  • ujjwal
WC :)

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rva.raghav
  • rva.raghav
what does n stand for?
rva.raghav
  • rva.raghav
correct please give best response
ujjwal
  • ujjwal
n is number of photons!

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