## rva.raghav Group Title At noon on a sunny day, there is a solar irradiance of 1 kW/m2 impinging on a solar panel that is 1 meter by 1.6 meters. To simplify the problem we assume here that the light is all the same wavelength λ=732 nm.Determine the number of photons per second incident on the panel. one year ago one year ago

1. ujjwal Group Title

The area of solar panel is 1.6 $$m^2$$. The energy of photons striking 1 $$m^2$$ per sec is 1000 J So, the energy of photons striking 1.6 $$m^2$$ per sec is 1.6 $$\times$$1000=1600 J Now you need to find the number of photons which will have energy of 1600 J let that number be n So,$nh\frac{c}{\lambda}=1600$where h is plank's constant and c is velocity of light you have $$\lambda$$. Find n

2. rva.raghav Group Title

thks ujjwal

3. ujjwal Group Title

WC :)

4. rva.raghav Group Title

what does n stand for?

5. rva.raghav Group Title

correct please give best response

6. ujjwal Group Title

n is number of photons!