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ksaimouli
 4 years ago
use the 2nd derivative test to find the local extrema for the function
ksaimouli
 4 years ago
use the 2nd derivative test to find the local extrema for the function

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ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1352126604670:dw

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.1use the product rule

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1352126927234:dw

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1set =0 and find critical points

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1352127080538:dw

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1352127105772:dw

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.1\[ \large y'=e^x+xe^x=(1+x)e^x \]

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1dont factor the first one yet

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.1so \[ \large y''=e^x+(1+x)e^x=(2+x)e^x \]

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1352127282428:dw

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.1\[ \large 0=y'=(1+x)e^x \]

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1wait how did u get 1 it is (x+2)e^x right so e^x=0 (x+2)=0

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.1no. u r looking for extrema.

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1i know i am finding the critical points by setting=0 and then using sign chart i will find it

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.1yes. the only critical point is x=1

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1u r using first derivative right

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.1then \[ \large y''(1)=(2+(1))e^{1}=(1)e^{1}>0 \]

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.1yes i'm using the first derivative

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.1but question asks for second derivative

helder_edwin
 4 years ago
Best ResponseYou've already chosen the best response.1so y'' is positive when x=1. what does this tell u??
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