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ksaimouli
Group Title
use the 2nd derivative test to find the local extrema for the function
 2 years ago
 2 years ago
ksaimouli Group Title
use the 2nd derivative test to find the local extrema for the function
 2 years ago
 2 years ago

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ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1352126604670:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
@Aperogalics
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
use the product rule
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i got that
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1352126927234:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
set =0 and find critical points
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
u got it wrong!!!
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1352127080538:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1352127105772:dw
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
\[ \large y'=e^x+xe^x=(1+x)e^x \]
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dont factor the first one yet
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
so \[ \large y''=e^x+(1+x)e^x=(2+x)e^x \]
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
dw:1352127282428:dw
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
okay after that
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i dont get that part
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
solve y'=0
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
what is e^x=0
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
\[ \large 0=y'=(1+x)e^x \]
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
so x=1
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
wait how did u get 1 it is (x+2)e^x right so e^x=0 (x+2)=0
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
no. u r looking for extrema.
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
i know i am finding the critical points by setting=0 and then using sign chart i will find it
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
yes. the only critical point is x=1
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
u r using first derivative right
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
then \[ \large y''(1)=(2+(1))e^{1}=(1)e^{1}>0 \]
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
yes i'm using the first derivative
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.1
but question asks for second derivative
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
so y'' is positive when x=1. what does this tell u??
 2 years ago
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