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What is the magnetic force acting on an electron if its speed is 3.0 × 106 meters/second and the direction is perpendicular to a magnetic field of 0.020 teslas? The value of q = 1.6 × 1019 coulombs.
A. F = 0 newtons
B. F = 6.0 × 1015 newtons
C. F = 9.6 × 1015 newtons
D. F = 3.0 × 1016 newtons
E. F = 3.2 × 1021 newtons
 one year ago
 one year ago
What is the magnetic force acting on an electron if its speed is 3.0 × 106 meters/second and the direction is perpendicular to a magnetic field of 0.020 teslas? The value of q = 1.6 × 1019 coulombs. A. F = 0 newtons B. F = 6.0 × 1015 newtons C. F = 9.6 × 1015 newtons D. F = 3.0 × 1016 newtons E. F = 3.2 × 1021 newtons
 one year ago
 one year ago

This Question is Closed

ujjwalBest ResponseYou've already chosen the best response.0
The magnitude of force is given by \[F=q(v\times B)\]
 one year ago
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