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Here's the question you clicked on:
henpen
\[ \frac{dy}{dx}=\sqrt{y^2-1} \]
Boundary conditions are\[y(a)=y(-a)=1\]
\[\frac{dy}{\sqrt{y^2-1}}=dx\] Separation of variables. Now integrate both sides. :
Why didn't I see that?! Thanks
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