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henpen

  • 3 years ago

\[ \frac{dy}{dx}=\sqrt{y^2-1} \]

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  1. henpen
    • 3 years ago
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    Boundary conditions are\[y(a)=y(-a)=1\]

  2. myininaya
    • 3 years ago
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    \[\frac{dy}{\sqrt{y^2-1}}=dx\] Separation of variables. Now integrate both sides. :

  3. henpen
    • 3 years ago
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    Why didn't I see that?! Thanks

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