Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

LaddiusMaximus

  • 2 years ago

find the linear approximation of the fnct f(x)=sqrt(1-x) at a=0 and use it to approximate the numbers (sqrt0.9) and (sqrt0.99)

  • This Question is Closed
  1. myininaya
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So do you know how to find the tangent line at x=0?

  2. myininaya
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[y=mx+b <--\text{ line} \] m=f ' (x=a)=f ' (x=0)=f ' (0) You need to find f ' (x). Then evaluate f ' (x) at x=0. y=f ' (0) x + b We still need to find b though. But we are given a point on this line (0,f(0)) What is f(0)? We will plug in what we know to find what b is: f(0)=f ' (0) * 0 +b f(0)=b SO great.We have the tangent line here at x=0 is y=f ' (0) x + f(0)

  3. myininaya
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Let me know when you find what f ' (0) and f(0) is, then I will give you further assistance.

  4. LaddiusMaximus
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i was showed some different L(x)= f(a)+f'(a)(x-a)

  5. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.