anonymous
  • anonymous
place the fraction in order from least to greatest ,
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
3/7 1/3 2/5 and 3/8
myininaya
  • myininaya
\[\frac{3}{7}, \frac{1}{3}, \frac{2}{5}, \frac{3}{8}\] You could find a common denominator What do 7,3,5, and 8 divide? You could force a common denominator and just take all of their denominators and multiply them to find a common denominator like so: \[\frac{3}{7}=\frac{3}{7} \cdot \frac{3}{3} \cdot \frac{5}{5} \cdot \frac{8}{8} \] \[\frac{1}{3}=\frac{1}{3} \cdot \frac{7}{7} \cdot \frac{5}{5} \cdot \frac{8}{8}\] \[\frac{2}{5}=\frac{2}{5} \cdot \frac{7}{7} \cdot \frac{3}{3} \cdot \frac{8}{8}\] \[\frac{3}{8}=\frac{3}{8} \cdot \frac{7}{7} \cdot \frac{3}{3} \cdot \frac{5}{5}\] Since all the denominators are the same, all you have to do is compare the tops. The tops of: \[\frac{3(3)(5)(8)}{7(3)(5)(8)} , \frac{1(7)(5)(8)}{3(7)(5)(8)}, \frac{2(7)(3)(8)}{5(7)(3)(8)}, \frac{3(7)(3)(5)}{8(7)(3)(5)}\]
myininaya
  • myininaya
So which is the least: 3(3)(5)(8) , 1(7)(5)(8), 2(7)(3)(8) , 3(7)(3)(5)

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myininaya
  • myininaya
Multiply first. This may be more revealing to you.
myininaya
  • myininaya
You could also write each fraction as a decimal. These are the two ways I prefer.

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