Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
lysa_nicole4794
Group Title
Find the most general antiderivative of the function.
g(t) = (5 + t + t^2)/ square root of t
 one year ago
 one year ago
lysa_nicole4794 Group Title
Find the most general antiderivative of the function. g(t) = (5 + t + t^2)/ square root of t
 one year ago
 one year ago

This Question is Closed

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[g(t)=\frac{5+t+t^2}{t^\frac{1}{2}}=\frac{5}{t^\frac{1}{2}}+\frac{t}{t^\frac{1}{2}}+\frac{t^2}{t^\frac{1}{2}}=5t^{\frac{1}{2}}+t^{1\frac{1}{2}}+t^{2\frac{1}{2}}\] \[g(t)=5t^{\frac{1}{2}}+t^\frac{1}{2}+t^{\frac{3}{2}}\] Find the antiderivative of each term using \[f(t)=t^n => F(t)=\frac{t^{n+1}}{n+1} \text{ where } F'=f \text{ and } n \neq 1\]
 one year ago

lysa_nicole4794 Group TitleBest ResponseYou've already chosen the best response.0
thanks!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.