A community for students. Sign up today!
Here's the question you clicked on:
← 55 members online
 0 viewing
 2 years ago
Find the most general antiderivative of the function.
g(t) = (5 + t + t^2)/ square root of t
 2 years ago
Find the most general antiderivative of the function. g(t) = (5 + t + t^2)/ square root of t

This Question is Closed

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[g(t)=\frac{5+t+t^2}{t^\frac{1}{2}}=\frac{5}{t^\frac{1}{2}}+\frac{t}{t^\frac{1}{2}}+\frac{t^2}{t^\frac{1}{2}}=5t^{\frac{1}{2}}+t^{1\frac{1}{2}}+t^{2\frac{1}{2}}\] \[g(t)=5t^{\frac{1}{2}}+t^\frac{1}{2}+t^{\frac{3}{2}}\] Find the antiderivative of each term using \[f(t)=t^n => F(t)=\frac{t^{n+1}}{n+1} \text{ where } F'=f \text{ and } n \neq 1\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.