## psk981 Group Title integrate f(x,y)= x^2 +y over a triangular region bounded by (0,0), (1,0),(0,1) one year ago one year ago

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draw the region, what is the equation of the line between (1,0) and (0,1) ?

2. psk981 Group Title

|dw:1352136497588:dw|

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yes

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only reversed, gotta have the constant last or you won't get a constant as an answer!

5. psk981 Group Title

how would my integrals look

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the inner integral is bounded by the function -x, the outer by the constants

7. psk981 Group Title

after i solve it i get 2/3

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I get 3/4 can you show your work?

9. psk981 Group Title

$\int\limits_{0}^{1} \int\limits_{0}^{-x} x^{2}+y dydx$ |dw:1352137141341:dw| |dw:1352137253709:dw|

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|dw:1352137394567:dw|you dropped the /2 part...

11. psk981 Group Title

ok sweet i got it

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13. psk981 Group Title

but order doesn't matter if you have constants

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If both bounds are constants then often not, but sometimes the integral is only possible in a certain order. In this case we have the bounds as one constant, and one function. You could have done this one in the other order, but you would have to change the inner function to terms of yu.

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terms of y*

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@psk981 I just realized we messed this one up :P

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|dw:1352139848664:dw|

18. psk981 Group Title

how so

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this function ain't -x, it's 1-x|dw:1352139902007:dw|

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so that should be the inner bound

21. psk981 Group Title

so goes from 0 to 1-x

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yes

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and|dw:1352140168346:dw|so I totally space out on the last one, sorry

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$\int_0^1\int_0^{1-x}x^2+ydydx=\int_0^1\left.x^2y+\frac{y^2}2\right|_0^{1-x}dx$