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At what point on the paraboloid y = x^2+z^2 is the tangent plane parallel to the plane x+2y+3z=1?

Mathematics
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find the gradient of the surface
<2,-1,2>
grad f=<2x, -1, 2z>

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Other answers:

yes
ok, now since we can't plug in anything that will change y, let's multiply the gradient by a scalar to get the j-component equal to 2 like it is for the plane
multiply by -2
right, and so we get?
grad f=<-4x,2y, -4z>
grad f=<-4x,2,-4z> that y can't just appear from nowhere
so what value of x makes the i-components equal for the plane and grad f ? what value of z makes the k-components equal?
x=1/2and z= 3/2 ???
from the equation as we have it we need x=-1/4 and z=-3/4
ok.
that's all then... boring problem
why qns with sphere have 2 sets of points?
hm... seems strange that y does not matter. Maybe I messed this one up :P
sorry? what do you mean?
for qns with sphere has 2 sets of points as ans why?
what do you mean it has 2 sets of points?
the ans fot this qn is (-1/4, -2,-3/4)
the way we did it it looks like y does not matter, so (-1/4,y,-3/4) seems strange that y does not matter though, maybe I made a mistake... not sure
so the point for y is 0 or -1?
neither, the result says y can be anything, so just write y=y
isnt y a function if x and z to begin with? y = x^2 + z^2; therefore y=1/4

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