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alainabbyboo22

  • 2 years ago

Calculate the value of x, given line segment FM = 3x and line segment MN = x + 40. A. 13.3 B. 10 C. 40. D. 20

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  1. alainabbyboo22
    • 2 years ago
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  2. ash2326
    • 2 years ago
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    @alainabbyboo22 Given that the arcs NM and FM are equal

  3. ash2326
    • 2 years ago
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    so chords will be equal too NM=FM Can you solve it from here ?

  4. alainabbyboo22
    • 2 years ago
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    i'm confused on this . what do i need to do ?

  5. ash2326
    • 2 years ago
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    We have the arcs equal as it's indicated in the diagram, isn't it?

  6. alainabbyboo22
    • 2 years ago
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    ya

  7. ash2326
    • 2 years ago
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    so the chords ( the straight lines ) NM and FM will be equal NM=FM

  8. alainabbyboo22
    • 2 years ago
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    then what do i do ?

  9. ash2326
    • 2 years ago
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    You are given the values of NM and FM in the question. Plug them here : NM=FM

  10. ash2326
    • 2 years ago
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    NM=x+40 FM=3x NM=FM so \[x+40=3x\] Can you solve this @alainabbyboo22 ?

  11. alainabbyboo22
    • 2 years ago
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    how do i solve that though ? what do i do ?

  12. alainabbyboo22
    • 2 years ago
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    i am sorry if i am irritating you with this but i just don't quite understand this stuff

  13. ash2326
    • 2 years ago
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    No problem. I 'll help you figure this out :)

  14. alainabbyboo22
    • 2 years ago
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    thanks so much ! (: i really appreciate it ! thank you for taking your time out of your day to try and help me out on this !

  15. ash2326
    • 2 years ago
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    We are all here to help. You're welcome

  16. ash2326
    • 2 years ago
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    Can you solve this equation for x ? \[x+4=6\]

  17. alainabbyboo22
    • 2 years ago
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    would i take the numbers from the answer choices and plug them into x or would i add 4 + 6 ?

  18. ash2326
    • 2 years ago
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    It's just an example, unrelated to the question. Do you know how to solve these type of equations?

  19. alainabbyboo22
    • 2 years ago
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    no /:

  20. ash2326
    • 2 years ago
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    Ok. I'll explain you

  21. ash2326
    • 2 years ago
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    Her we have x+4=6 it means that x+4 is equal to 6 x is a variable, we need to find its value which will make this equation true. There is only one value of x which will make this equation true. It's easy to find that :) We need to modify it in such a way that we have x separate and no or no.s separate. \[x+\underline 4=6\] I can see that 4 is on left side. Want to remove it !! So I subtract both sides by 4, it's important to remember that whatever operation I do be it add, subtract, multiply or divide. I have to do on both sides not one side \[x+4-4=6-4\] Now I'll simplify \[x+\cancel 4- \cancel 4=2\] \[x+0=2\] or \[x=2\] Do you get this?

  22. alainabbyboo22
    • 2 years ago
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    alright i got that part now !

  23. ash2326
    • 2 years ago
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    good, similarly we have to find the value of x here. We know FM=MN so \[3x=x+40\] here x on the right side is to be removed, what can you do remove x from right side? remember operations on both sides !!

  24. alainabbyboo22
    • 2 years ago
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    okay now i'm lost again ..

  25. ash2326
    • 2 years ago
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    I'll give you a hint, subtract both sides by x. what would you get?

  26. alainabbyboo22
    • 2 years ago
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    the right side would 38 and the left side would be 1 .

  27. ash2326
    • 2 years ago
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    What did you subtract?

  28. alainabbyboo22
    • 2 years ago
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    am i right ?

  29. alainabbyboo22
    • 2 years ago
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    i subtracted 40-2 and 3-2

  30. ash2326
    • 2 years ago
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    You made a mistake somewhere. No worries, I'll guide you \[3x=x+40\] subtract both sides by x, because we want to remove x from the right side \[3x-x=x+40-x\] Now what would you get?

  31. alainabbyboo22
    • 2 years ago
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    3x=40 ?

  32. ash2326
    • 2 years ago
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    we have 3x-x, on left side or 3x-1x, what would you get on the left side?

  33. alainabbyboo22
    • 2 years ago
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    x + 38

  34. ash2326
    • 2 years ago
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    we have \[3x-1x=40\] or \[x(3-1)=40\] What would you get next?

  35. ash2326
    • 2 years ago
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    what's 3-1 ?

  36. alainabbyboo22
    • 2 years ago
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    2

  37. ash2326
    • 2 years ago
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    @alainabbyboo22 ?

  38. alainabbyboo22
    • 2 years ago
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    i got 2

  39. alainabbyboo22
    • 2 years ago
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    where do i go from there now ?

  40. alainabbyboo22
    • 2 years ago
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    @ash2326

  41. ash2326
    • 2 years ago
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    so you have \[x \times 2=40\] If you subtract variables, like 4x-2x just subtract 4-2=2 and put the 2 before x but if you have x-x or 9x-9x it'll become 0 do you get this?

  42. alainabbyboo22
    • 2 years ago
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    yes i see now . okay what do i do to get my answer ?

  43. ash2326
    • 2 years ago
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    now what do we have?

  44. alainabbyboo22
    • 2 years ago
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    2x = 40

  45. ash2326
    • 2 years ago
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    divide both sides by 2, what would you get?

  46. alainabbyboo22
    • 2 years ago
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    2 and 20

  47. ash2326
    • 2 years ago
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    \[\frac{2\times x}{2}=\frac{40}{2}\] \[\frac{\cancel 2 \times x}{\cancel 2}=20\] what would you get for x?

  48. alainabbyboo22
    • 2 years ago
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    2

  49. ash2326
    • 2 years ago
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    how you would get 2???

  50. alainabbyboo22
    • 2 years ago
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    i'm lost .. again .

  51. alainabbyboo22
    • 2 years ago
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    would it be 10 ?

  52. alainabbyboo22
    • 2 years ago
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    because 20/2

  53. alainabbyboo22
    • 2 years ago
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    ?

  54. ash2326
    • 2 years ago
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    we have \[2x=40\] divide both sides by 2 only once

  55. alainabbyboo22
    • 2 years ago
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    1x = 20

  56. ash2326
    • 2 years ago
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    yeah so x =???

  57. alainabbyboo22
    • 2 years ago
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    20 !

  58. ash2326
    • 2 years ago
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    good, did you understand this?

  59. alainabbyboo22
    • 2 years ago
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    yes now i do ! thank you very much ! (:

  60. ash2326
    • 2 years ago
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    Welcome and feel free to contact me here, Anytime for help !!

  61. alainabbyboo22
    • 2 years ago
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    thanks !! (: have a great day !

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