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alainabbyboo22
 3 years ago
Calculate the value of x, given line segment FM = 3x and line segment MN = x + 40.
A. 13.3
B. 10
C. 40.
D. 20
alainabbyboo22
 3 years ago
Calculate the value of x, given line segment FM = 3x and line segment MN = x + 40. A. 13.3 B. 10 C. 40. D. 20

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ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1@alainabbyboo22 Given that the arcs NM and FM are equal

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1so chords will be equal too NM=FM Can you solve it from here ?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0i'm confused on this . what do i need to do ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1We have the arcs equal as it's indicated in the diagram, isn't it?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1so the chords ( the straight lines ) NM and FM will be equal NM=FM

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0then what do i do ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1You are given the values of NM and FM in the question. Plug them here : NM=FM

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1NM=x+40 FM=3x NM=FM so \[x+40=3x\] Can you solve this @alainabbyboo22 ?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0how do i solve that though ? what do i do ?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0i am sorry if i am irritating you with this but i just don't quite understand this stuff

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1No problem. I 'll help you figure this out :)

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0thanks so much ! (: i really appreciate it ! thank you for taking your time out of your day to try and help me out on this !

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1We are all here to help. You're welcome

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1Can you solve this equation for x ? \[x+4=6\]

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0would i take the numbers from the answer choices and plug them into x or would i add 4 + 6 ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1It's just an example, unrelated to the question. Do you know how to solve these type of equations?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1Her we have x+4=6 it means that x+4 is equal to 6 x is a variable, we need to find its value which will make this equation true. There is only one value of x which will make this equation true. It's easy to find that :) We need to modify it in such a way that we have x separate and no or no.s separate. \[x+\underline 4=6\] I can see that 4 is on left side. Want to remove it !! So I subtract both sides by 4, it's important to remember that whatever operation I do be it add, subtract, multiply or divide. I have to do on both sides not one side \[x+44=64\] Now I'll simplify \[x+\cancel 4 \cancel 4=2\] \[x+0=2\] or \[x=2\] Do you get this?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0alright i got that part now !

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1good, similarly we have to find the value of x here. We know FM=MN so \[3x=x+40\] here x on the right side is to be removed, what can you do remove x from right side? remember operations on both sides !!

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0okay now i'm lost again ..

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1I'll give you a hint, subtract both sides by x. what would you get?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0the right side would 38 and the left side would be 1 .

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0i subtracted 402 and 32

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1You made a mistake somewhere. No worries, I'll guide you \[3x=x+40\] subtract both sides by x, because we want to remove x from the right side \[3xx=x+40x\] Now what would you get?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1we have 3xx, on left side or 3x1x, what would you get on the left side?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1we have \[3x1x=40\] or \[x(31)=40\] What would you get next?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0where do i go from there now ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1so you have \[x \times 2=40\] If you subtract variables, like 4x2x just subtract 42=2 and put the 2 before x but if you have xx or 9x9x it'll become 0 do you get this?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0yes i see now . okay what do i do to get my answer ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1divide both sides by 2, what would you get?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{2\times x}{2}=\frac{40}{2}\] \[\frac{\cancel 2 \times x}{\cancel 2}=20\] what would you get for x?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0i'm lost .. again .

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0would it be 10 ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1we have \[2x=40\] divide both sides by 2 only once

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1good, did you understand this?

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0yes now i do ! thank you very much ! (:

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.1Welcome and feel free to contact me here, Anytime for help !!

alainabbyboo22
 3 years ago
Best ResponseYou've already chosen the best response.0thanks !! (: have a great day !
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