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Calculate the value of x, given line segment FM = 3x and line segment MN = x + 40. A. 13.3 B. 10 C. 40. D. 20

Geometry
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@alainabbyboo22 Given that the arcs NM and FM are equal
so chords will be equal too NM=FM Can you solve it from here ?

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Other answers:

i'm confused on this . what do i need to do ?
We have the arcs equal as it's indicated in the diagram, isn't it?
ya
so the chords ( the straight lines ) NM and FM will be equal NM=FM
then what do i do ?
You are given the values of NM and FM in the question. Plug them here : NM=FM
NM=x+40 FM=3x NM=FM so \[x+40=3x\] Can you solve this @alainabbyboo22 ?
how do i solve that though ? what do i do ?
i am sorry if i am irritating you with this but i just don't quite understand this stuff
No problem. I 'll help you figure this out :)
thanks so much ! (: i really appreciate it ! thank you for taking your time out of your day to try and help me out on this !
We are all here to help. You're welcome
Can you solve this equation for x ? \[x+4=6\]
would i take the numbers from the answer choices and plug them into x or would i add 4 + 6 ?
It's just an example, unrelated to the question. Do you know how to solve these type of equations?
no /:
Ok. I'll explain you
Her we have x+4=6 it means that x+4 is equal to 6 x is a variable, we need to find its value which will make this equation true. There is only one value of x which will make this equation true. It's easy to find that :) We need to modify it in such a way that we have x separate and no or no.s separate. \[x+\underline 4=6\] I can see that 4 is on left side. Want to remove it !! So I subtract both sides by 4, it's important to remember that whatever operation I do be it add, subtract, multiply or divide. I have to do on both sides not one side \[x+4-4=6-4\] Now I'll simplify \[x+\cancel 4- \cancel 4=2\] \[x+0=2\] or \[x=2\] Do you get this?
alright i got that part now !
good, similarly we have to find the value of x here. We know FM=MN so \[3x=x+40\] here x on the right side is to be removed, what can you do remove x from right side? remember operations on both sides !!
okay now i'm lost again ..
I'll give you a hint, subtract both sides by x. what would you get?
the right side would 38 and the left side would be 1 .
What did you subtract?
am i right ?
i subtracted 40-2 and 3-2
You made a mistake somewhere. No worries, I'll guide you \[3x=x+40\] subtract both sides by x, because we want to remove x from the right side \[3x-x=x+40-x\] Now what would you get?
3x=40 ?
we have 3x-x, on left side or 3x-1x, what would you get on the left side?
x + 38
we have \[3x-1x=40\] or \[x(3-1)=40\] What would you get next?
what's 3-1 ?
2
i got 2
where do i go from there now ?
so you have \[x \times 2=40\] If you subtract variables, like 4x-2x just subtract 4-2=2 and put the 2 before x but if you have x-x or 9x-9x it'll become 0 do you get this?
yes i see now . okay what do i do to get my answer ?
now what do we have?
2x = 40
divide both sides by 2, what would you get?
2 and 20
\[\frac{2\times x}{2}=\frac{40}{2}\] \[\frac{\cancel 2 \times x}{\cancel 2}=20\] what would you get for x?
2
how you would get 2???
i'm lost .. again .
would it be 10 ?
because 20/2
?
we have \[2x=40\] divide both sides by 2 only once
1x = 20
yeah so x =???
20 !
good, did you understand this?
yes now i do ! thank you very much ! (:
Welcome and feel free to contact me here, Anytime for help !!
thanks !! (: have a great day !

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