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sandy524Best ResponseYou've already chosen the best response.0
i now know that its sin(x)(2cos(x)+1)
 one year ago

sandy524Best ResponseYou've already chosen the best response.0
can yu guys help me find the critical points
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Are you sure it ask you to find f'(x) on [a,b]?
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
If so, you did that. You are done.
 one year ago

sandy524Best ResponseYou've already chosen the best response.0
yes. may you help me find the critical points of this now
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Set f'(x)=0 and solve for x to find the critical numbers.
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
You only need to solve this on the interval [0,2 pi]
 one year ago

sandy524Best ResponseYou've already chosen the best response.0
can we do it together please
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
You are already factored f'(x) Now set both factors equal to 0.
 one year ago

sandy524Best ResponseYou've already chosen the best response.0
how? can we work out the problem
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Yes. I'm walking you through it. You have sin(x)*(1+2cos(x))=0 Set both factors equal to 0.
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Just like if you have a*b=0 then either a=0 or b=0 or both=0
 one year ago

sandy524Best ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=sin%28x%29%282cos%28x%29%2B1%29%3D0
 one year ago

sandy524Best ResponseYou've already chosen the best response.0
im confused about the results
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Use your unit circle. Keep in mind you only have to look between 0 and 2pi
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
You have sin(x)=0 or 1+2cos(x)=0 Solve both of these for the trig function. Solve the first one for sin(x) and solve the second one for cos(x). Tell me what you get after doing this.
 one year ago

myininayaBest ResponseYou've already chosen the best response.0
Well you are trying to solve sin(x)=0 for x. You could divide both sides by 1 since 1 will never be 0. Try solving this: sin(x)=0 Then we will come back to 1+2cos(x)=0
 one year ago
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