anonymous
  • anonymous
find the derivative of f(x) = cos(x) − sin^2(x) on [0,2pi]
Mathematics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
i now know that its -sin(x)(2cos(x)+1)
anonymous
  • anonymous
can yu guys help me find the critical points
myininaya
  • myininaya
Are you sure it ask you to find f'(x) on [a,b]?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

myininaya
  • myininaya
If so, you did that. You are done.
anonymous
  • anonymous
yes. may you help me find the critical points of this now
myininaya
  • myininaya
Set f'(x)=0 and solve for x to find the critical numbers.
myininaya
  • myininaya
You only need to solve this on the interval [0,2 pi]
anonymous
  • anonymous
can we do it together please
myininaya
  • myininaya
You are already factored f'(x) Now set both factors equal to 0.
anonymous
  • anonymous
how? can we work out the problem
anonymous
  • anonymous
step by step please
myininaya
  • myininaya
Yes. I'm walking you through it. You have -sin(x)*(1+2cos(x))=0 Set both factors equal to 0.
anonymous
  • anonymous
ok
myininaya
  • myininaya
Just like if you have a*b=0 then either a=0 or b=0 or both=0
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=-sin%28x%29%282cos%28x%29%2B1%29%3D0
anonymous
  • anonymous
this is all i have
anonymous
  • anonymous
im confused about the results
myininaya
  • myininaya
Use your unit circle. Keep in mind you only have to look between 0 and 2pi
myininaya
  • myininaya
You have -sin(x)=0 or 1+2cos(x)=0 Solve both of these for the trig function. Solve the first one for sin(x) and solve the second one for cos(x). Tell me what you get after doing this.
anonymous
  • anonymous
-sinx=pin
anonymous
  • anonymous
\[\pi n\]
myininaya
  • myininaya
Well you are trying to solve -sin(x)=0 for x. You could divide both sides by -1 since -1 will never be 0. Try solving this: sin(x)=0 Then we will come back to 1+2cos(x)=0

Looking for something else?

Not the answer you are looking for? Search for more explanations.