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psk981Best ResponseYou've already chosen the best response.1
\[\int\limits_{0}^{2}\int\limits_{0}^{\sqrt{4y ^{2}}} x ^{2}+y^{2} dxdy\]
 one year ago

psk981Best ResponseYou've already chosen the best response.1
i know it becomes \[r^{2} r dr dTheta\]
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
yes, which simplifies to\[r^3drd\theta\]where are you stuck?
 one year ago

psk981Best ResponseYou've already chosen the best response.1
the sqrt term becomes x^2+y^2= 4 right
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
x^2+y^2=r^2 what is the radius of the circle in question?
 one year ago

psk981Best ResponseYou've already chosen the best response.1
so i should get r^4/4 evaluated from 0 to 2 then i should get 4 dtheta
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
and what are the bounds on theta?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
remember that sqrt(4y^2) is only the *top* of the circle, the bottom would require a negative sign, so the bounds on theta are only...?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
no problem, happy to help
 one year ago
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