Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

psk981 Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{0}^{2}\int\limits_{0}^{\sqrt{4y ^{2}}} x ^{2}+y^{2} dxdy\]
 one year ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
i know it becomes \[r^{2} r dr dTheta\]
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
yes, which simplifies to\[r^3drd\theta\]where are you stuck?
 one year ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
the sqrt term becomes x^2+y^2= 4 right
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
x^2+y^2=r^2 what is the radius of the circle in question?
 one year ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
so i should get r^4/4 evaluated from 0 to 2 then i should get 4 dtheta
 one year ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
radius should be 2
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
and what are the bounds on theta?
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
remember that sqrt(4y^2) is only the *top* of the circle, the bottom would require a negative sign, so the bounds on theta are only...?
 one year ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
so would i ge 4 pi
 one year ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
ur a life saver
 one year ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
no problem, happy to help
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.