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anonymous
 4 years ago
change to polar and then integrate
anonymous
 4 years ago
change to polar and then integrate

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{2}\int\limits_{0}^{\sqrt{4y ^{2}}} x ^{2}+y^{2} dxdy\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know it becomes \[r^{2} r dr dTheta\]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1yes, which simplifies to\[r^3drd\theta\]where are you stuck?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the sqrt term becomes x^2+y^2= 4 right

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1x^2+y^2=r^2 what is the radius of the circle in question?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i should get r^4/4 evaluated from 0 to 2 then i should get 4 dtheta

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1and what are the bounds on theta?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1remember that sqrt(4y^2) is only the *top* of the circle, the bottom would require a negative sign, so the bounds on theta are only...?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1no problem, happy to help
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