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psk981 Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{0}^{2}\int\limits_{0}^{\sqrt{4y ^{2}}} x ^{2}+y^{2} dxdy\]
 2 years ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
i know it becomes \[r^{2} r dr dTheta\]
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
yes, which simplifies to\[r^3drd\theta\]where are you stuck?
 2 years ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
the sqrt term becomes x^2+y^2= 4 right
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
x^2+y^2=r^2 what is the radius of the circle in question?
 2 years ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
so i should get r^4/4 evaluated from 0 to 2 then i should get 4 dtheta
 2 years ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
radius should be 2
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
and what are the bounds on theta?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
remember that sqrt(4y^2) is only the *top* of the circle, the bottom would require a negative sign, so the bounds on theta are only...?
 2 years ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
so would i ge 4 pi
 2 years ago

psk981 Group TitleBest ResponseYou've already chosen the best response.1
ur a life saver
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
no problem, happy to help
 2 years ago
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