bmelyk
I just wanna get my answer checked:



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bmelyk
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The height at time t (s) of a weight, oscillating up and down at the end of a spring is given below.
s(t) = 400 + 90sin(t)

bmelyk
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a) Find the velocity at t = π/3 s.
b) Find the acceleration at t = π/3 s

bmelyk
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so for a) my equation i had was 90sin(t)
and b) 90cos(t)

bmelyk
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wondering if those are right.

hartnn
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for velocity, u differentiate once, for acceleration, u differentiate twice.

hartnn
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so NO

hartnn
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first derivative of s(t) = 400 + 90sin(t) is ??

bmelyk
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90cos(t) ??

hartnn
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yes, thats your velocity

hartnn
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and acceleration ?

bmelyk
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90sin(t)

hartnn
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thats correct also :)

hartnn
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now just put t values

bmelyk
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so the answers are:
A) 45
b) 45 sqrt3
???

hartnn
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yes.

bmelyk
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woo hoooo. : )