anonymous
  • anonymous
I just wanna get my answer checked:
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
The height at time t (s) of a weight, oscillating up and down at the end of a spring is given below. s(t) = 400 + 90sin(t)
anonymous
  • anonymous
a) Find the velocity at t = π/3 s. b) Find the acceleration at t = π/3 s
anonymous
  • anonymous
so for a) my equation i had was 90sin(t) and b) 90cos(t)

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anonymous
  • anonymous
wondering if those are right.
hartnn
  • hartnn
for velocity, u differentiate once, for acceleration, u differentiate twice.
hartnn
  • hartnn
so NO
hartnn
  • hartnn
first derivative of s(t) = 400 + 90sin(t) is ??
anonymous
  • anonymous
90cos(t) ??
hartnn
  • hartnn
yes, thats your velocity
hartnn
  • hartnn
and acceleration ?
anonymous
  • anonymous
-90sin(t)
hartnn
  • hartnn
thats correct also :)
hartnn
  • hartnn
now just put t values
anonymous
  • anonymous
so the answers are: A) 45 b) -45 sqrt3 ???
hartnn
  • hartnn
yes.
anonymous
  • anonymous
woo hoooo. : )

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