anonymous
  • anonymous
Write the expression as a single natural logarithm.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[3\ln x - 2\ln c\]
anonymous
  • anonymous
the c is closer to the ln like lnc
anonymous
  • anonymous
@jim_thompson5910

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jim_thompson5910
  • jim_thompson5910
Hint: Use the following identities \[\Large y*\ln(x) = \ln(x^y)\] \[\Large \ln(x)-\ln(y) = \ln\left(\frac{x}{y}\right)\]
anonymous
  • anonymous
huh?
jim_thompson5910
  • jim_thompson5910
|dw:1352158470384:dw|
jim_thompson5910
  • jim_thompson5910
becomes |dw:1352158488263:dw|
anonymous
  • anonymous
im confused whats with the y
jim_thompson5910
  • jim_thompson5910
it's just a general way of stating the rule
jim_thompson5910
  • jim_thompson5910
you can replace y with any number or variable you want
anonymous
  • anonymous
if this is as hard as the problem from earlier im just going to guess lol
jim_thompson5910
  • jim_thompson5910
examples: |dw:1352158554240:dw|
anonymous
  • anonymous
\[\ln x ^{3}c ^{2}\]
anonymous
  • anonymous
\[lnx ^{3}-lnc ^{2}\]
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
you're close though
anonymous
  • anonymous
thats what i got but im probley wrong
anonymous
  • anonymous
x is over c isnt it
jim_thompson5910
  • jim_thompson5910
it is
jim_thompson5910
  • jim_thompson5910
it should be \[\Large \ln\left(\frac{x^3}{c^2}\right)\]
anonymous
  • anonymous
thought so

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