A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
triple integrals in spherical coordinates
anonymous
 4 years ago
triple integrals in spherical coordinates

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}\int\limits_{}^{}\int\limits_{}^{}(x^2+y^2+z^2)^{5/2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know it going to be p^5 but what will the ingtegrals be

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1Do we have a region we're integrating over? D: Any boundaries like z=0, x=0 or anything? :O Or you're more concerned with just converting it correctly right now? :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it just states that it is the unit ball

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i guess the theta will be from 0 to 2pi right?

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1\[z= \rho \cos \phi\]\[x=\rho \cos \theta \sin \phi\]\[y=\rho \sin \theta \sin \phi\] \[(x^2+y^2+z^2)=(\rho^2)\] Oh oh you said you already figured that part out :) my bad. Yah theta will range from 0 to 2pi. Phi from 0 to pi I think... and Rho from 0 to our radius (1 since it's the UNIT ball).

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1\[\huge \int\limits_{\theta=0}^{2\pi}\int\limits_{\phi=0}^{\pi}\int\limits_{\rho=0}^{1}\rho^5 (\rho^2 \sin \phi d \rho d \phi d \theta)\] Somethinggggg like that. Thinkinggg..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeap its right thanks
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.