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math_proof Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{}\int\limits_{}^{}\int\limits_{}^{}(x^2+y^2+z^2)^{5/2}\]
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.0
i know it going to be p^5 but what will the ingtegrals be
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Do we have a region we're integrating over? D: Any boundaries like z=0, x=0 or anything? :O Or you're more concerned with just converting it correctly right now? :)
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.0
it just states that it is the unit ball
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
oh i see :)
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.0
so i guess the theta will be from 0 to 2pi right?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[z= \rho \cos \phi\]\[x=\rho \cos \theta \sin \phi\]\[y=\rho \sin \theta \sin \phi\] \[(x^2+y^2+z^2)=(\rho^2)\] Oh oh you said you already figured that part out :) my bad. Yah theta will range from 0 to 2pi. Phi from 0 to pi I think... and Rho from 0 to our radius (1 since it's the UNIT ball).
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \int\limits_{\theta=0}^{2\pi}\int\limits_{\phi=0}^{\pi}\int\limits_{\rho=0}^{1}\rho^5 (\rho^2 \sin \phi d \rho d \phi d \theta)\] Somethinggggg like that. Thinkinggg..
 one year ago

math_proof Group TitleBest ResponseYou've already chosen the best response.0
yeap its right thanks
 one year ago
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