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logynklode Group Title

Pre Calc. Can anyone help me?

  • 2 years ago
  • 2 years ago

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  1. 3psilon Group Title
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    What's the question?

    • 2 years ago
  2. findme Group Title
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    "Can anyone help me?"

    • 2 years ago
  3. findme Group Title
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    YES! :D

    • 2 years ago
  4. logynklode Group Title
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    • 2 years ago
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  5. findme Group Title
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    \[f(x) = \frac{ 2 }{ x^2-2x-3 }=\frac{ 2 }{ (x+1)(x-3) }\]

    • 2 years ago
  6. logynklode Group Title
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    okay

    • 2 years ago
  7. findme Group Title
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    That means the x cannot be -1, 3 so the domain (-infi, -1)U(-1, 3)U(3, infi)

    • 2 years ago
  8. findme Group Title
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    or x <-1, -1<x<3, x>3

    • 2 years ago
  9. logynklode Group Title
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    okay

    • 2 years ago
  10. findme Group Title
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    for x-intercept: set f(x)=0, then: \[0=\frac{ 2 }{ (x+1)(x-3) }\] since no x exist that satisfy the above equation, there is no x-intercept

    • 2 years ago
  11. findme Group Title
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    for y-intercept: set x = 0, then: \[f(0) = \frac{ 2 }{ (0+1)(0-3) }=\frac{ -2 }{ 3 }\] so the y-intercept is at the point (0, -2/3)

    • 2 years ago
  12. findme Group Title
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    To get the horizontal asymptote: divide every individual block in the equation by the highest power of x, which is x^2

    • 2 years ago
  13. logynklode Group Title
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    no x inct? no range?

    • 2 years ago
  14. findme Group Title
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    o lol, forgot about range and there's no x-int as I've explained

    • 2 years ago
  15. logynklode Group Title
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    okay

    • 2 years ago
  16. findme Group Title
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    sorry, I need to a lecture now, but here is the graph for reference. good luck :D

    • 2 years ago
  17. logynklode Group Title
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    okay.

    • 2 years ago
  18. logynklode Group Title
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    anyone?

    • 2 years ago
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