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What's the question?

"Can anyone help me?"

YES! :D

\[f(x) = \frac{ 2 }{ x^2-2x-3 }=\frac{ 2 }{ (x+1)(x-3) }\]

okay

That means the x cannot be -1, 3
so the domain (-infi, -1)U(-1, 3)U(3, infi)

or x <-1, -13

okay

no x inct? no range?

o lol, forgot about range
and there's no x-int as I've explained

okay

sorry, I need to a lecture now, but here is the graph for reference. good luck :D

okay.

anyone?