## anonymous 3 years ago Pre Calc. Can anyone help me?

1. 3psilon

What's the question?

2. anonymous

"Can anyone help me?"

3. anonymous

YES! :D

4. anonymous

5. anonymous

$f(x) = \frac{ 2 }{ x^2-2x-3 }=\frac{ 2 }{ (x+1)(x-3) }$

6. anonymous

okay

7. anonymous

That means the x cannot be -1, 3 so the domain (-infi, -1)U(-1, 3)U(3, infi)

8. anonymous

or x <-1, -1<x<3, x>3

9. anonymous

okay

10. anonymous

for x-intercept: set f(x)=0, then: $0=\frac{ 2 }{ (x+1)(x-3) }$ since no x exist that satisfy the above equation, there is no x-intercept

11. anonymous

for y-intercept: set x = 0, then: $f(0) = \frac{ 2 }{ (0+1)(0-3) }=\frac{ -2 }{ 3 }$ so the y-intercept is at the point (0, -2/3)

12. anonymous

To get the horizontal asymptote: divide every individual block in the equation by the highest power of x, which is x^2

13. anonymous

no x inct? no range?

14. anonymous

o lol, forgot about range and there's no x-int as I've explained

15. anonymous

okay

16. anonymous

sorry, I need to a lecture now, but here is the graph for reference. good luck :D

17. anonymous

okay.

18. anonymous

anyone?