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  1. helpmeplz311
    • 3 years ago
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    @yummydum

  2. helpmeplz311
    • 3 years ago
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    @mark_o.

  3. helpmeplz311
    • 3 years ago
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    hi yummy help plz

  4. helpmeplz311
    • 3 years ago
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    @JakeV8 hey can u still help real quick?

  5. helpmeplz311
    • 3 years ago
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    @jayz657 plz look at both images on the photobucket link above

  6. helpmeplz311
    • 3 years ago
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    help me i beg u ill fan u

  7. jayz657
    • 3 years ago
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    for the first pic your given width = 120yds and legnth= 53 yds its asking how much yards did they run so they are asking for perimeter perimeter = 2length + 2width perimeter = 2(120) + 2(53) perimeter = 240 + 106 = 346yards for 1 lap they ran 30 laps so you multiply that by 30 so 30(346) = 10380 yards is the total dist they ran

  8. helpmeplz311
    • 3 years ago
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    hmmm...ok can you tell me what to put in each square? abd is this problem no.4?

  9. helpmeplz311
    • 3 years ago
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    @mark_o.

  10. jayz657
    • 3 years ago
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    that was number 7 figure = rectangle formula needed = perimeter measurement to find = yards what dimension = 120 by 53 key words= 30 laps, how many yards did the team ran units = yards

  11. helpmeplz311
    • 3 years ago
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    oh tnx let me write that real quick

  12. helpmeplz311
    • 3 years ago
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    done

  13. jayz657
    • 3 years ago
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    number 8 figure = cylinder formula need = volume of cylinder measurement to find = cubic centimeter what dimension = 3 dimension? <- have someone else chekc on this key words = anything that has a number in it units = cubic centimeter

  14. helpmeplz311
    • 3 years ago
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    writes thank uuu

  15. jayz657
    • 3 years ago
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    number 4 figure = cylinder formula needed = volume of cylinder measurement to find = cubic inches what dimesion= 3 dimension? key words = anyhting that has numbers with it units = inches

  16. helpmeplz311
    • 3 years ago
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    tnxxx

  17. jayz657
    • 3 years ago
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    finally number 5 figure = circle formula needed = circumference measurement to find = feet what dimension = 2 dimension? key wordds = anything that has a number with it units = feet

  18. helpmeplz311
    • 3 years ago
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    tnx and six?

  19. helpmeplz311
    • 3 years ago
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    six is the last one.

  20. jayz657
    • 3 years ago
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    for 6 figure = rectangle formula needed = area mmeasurement to find = feet what dimention = 2d? key words = anything that has a number with it units = feet

  21. jayz657
    • 3 years ago
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    there you go

  22. helpmeplz311
    • 3 years ago
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    tnx!!!!! ur awesome

  23. jayz657
    • 3 years ago
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    np glad to help

  24. helpmeplz311
    • 3 years ago
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    rewards:fan+medal:)

  25. jayz657
    • 3 years ago
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    haha thanks

  26. helpmeplz311
    • 3 years ago
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    np:) u deserved both:) n a million more medals:)

  27. helpmeplz311
    • 3 years ago
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    oh jayz an unsharpened pencil has a hexagon base with an area 54 mm^2 and length of 200 mm. disregarding the lead, how much wood is needed to create the pencil?

  28. helpmeplz311
    • 3 years ago
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    @jayz657

  29. mark_o.
    • 3 years ago
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    8) the formula for volume in cubic cm, V= pi r^2 h V=pi(2)^2 (30)= ?

  30. helpmeplz311
    • 3 years ago
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    oh its like the rest... key words, units..etc not actually answering it

  31. helpmeplz311
    • 3 years ago
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    but, can u help me find those things in thiis problem?

  32. helpmeplz311
    • 3 years ago
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    an unsharpened pencil has a hexagon base with an area 54 mm^2 and length of 200 mm. disregarding the lead, how much wood is needed to create the pencil?

  33. mark_o.
    • 3 years ago
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    4) given h=4.5 inch diameter d=2.5 inch, its radius r=? r=d/2= 2.5/2 inch vol V= pi(r)^2 h V=pi(2.5/2)^2 (4.5)=____? cubic inch

  34. helpmeplz311
    • 3 years ago
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    okay

  35. helpmeplz311
    • 3 years ago
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    but can you please help me find those specific things in the problem about the pencil?

  36. helpmeplz311
    • 3 years ago
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    like thenunits,dimension,key words,etc?

  37. helpmeplz311
    • 3 years ago
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    hi jayz

  38. helpmeplz311
    • 3 years ago
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    help please?

  39. helpmeplz311
    • 3 years ago
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    I beg of you.

  40. mark_o.
    • 3 years ago
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    5) |dw:1352228533296:dw| circle circumference C=pi d, since we only need half C=pid/2 total perimeter needed P= semicircle C+d = (pi*d/.2) +2.25 = (pi*2.25/2)+2.25 =---?ft.

  41. helpmeplz311
    • 3 years ago
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    okay.

  42. helpmeplz311
    • 3 years ago
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    jayz help

  43. mark_o.
    • 3 years ago
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    6) painting 1 wall covers area A=10 ft x 12 ft = 120 ft now she wanted to paint 4 walls so area total of 4A= 4*10*12= 4*120=----?square ft

  44. helpmeplz311
    • 3 years ago
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    Thanks, Mark.

  45. omnomnom
    • 3 years ago
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    its sad that i wasnt tagged T_T

  46. helpmeplz311
    • 3 years ago
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    sorry om:(

  47. omnomnom
    • 3 years ago
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    T_T its okay.. :D

  48. helpmeplz311
    • 3 years ago
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    ill b sure to tag you from now on:) promise

  49. helpmeplz311
    • 3 years ago
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    hi jack

  50. omnomnom
    • 3 years ago
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    Lol... I'm not sure i i will help much but OKAAAAAAAAAAY :D

  51. helpmeplz311
    • 3 years ago
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    ok then,it is settled. i gtg,tnx everyone for ur help.

  52. omnomnom
    • 3 years ago
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    Lol i did nothing :P And Byeeeeeeeeeeeee :D

  53. mark_o.
    • 3 years ago
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    7) on some international conversion 1 lap=437.44 yards 30 laps= _____? yds sol. xyds 30 laps ----------- = ---- ------ 437.44 yds 1 lap x=437.44(30)/1= _______?yds

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