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sabika13

  • 3 years ago

How do I solve this using identity: cos^2x/(1+2sinx-3sin^2x) = (1+sinx)/(1+3sinx)

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  1. Libniz
    • 3 years ago
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    let sin (x) be b

  2. sabika13
    • 3 years ago
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    i have to use trig identities tho^

  3. Libniz
    • 3 years ago
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    (1+2sinx-3sin^2x) 1+2b-3 b^2 = (1+3b)(1-b)

  4. Libniz
    • 3 years ago
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    cos^2x use identiry sin^2(x)+cos^2(x)=1 cos^2=1-sin^2(x)---->1-b^2 1-b^2=(1+b)(1-b)

  5. Libniz
    • 3 years ago
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    (1+b)(1-b) -------------- (1+3b)(1-b) (1-b) cancels leaving (1+b) ------------------ (1+3b) remember b=sin(x) 1+

  6. sabika13
    • 3 years ago
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    thanks

  7. Libniz
    • 3 years ago
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    no problem

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