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Use synthetic division to find P(3) for P(x) = x^4 – 6x^3 – 4x^2 – 6x – 2.
 one year ago
 one year ago
Use synthetic division to find P(3) for P(x) = x^4 – 6x^3 – 4x^2 – 6x – 2.
 one year ago
 one year ago

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richywBest ResponseYou've already chosen the best response.1
\[P(x)=x4−6x2−4x2−6x−2\] The polynomial remainder theorem says that If a polynomial \(P(x)\) is divided by \((x−r)\), then the remainder is a constant given by \(P(r)\).
 one year ago

richywBest ResponseYou've already chosen the best response.1
so in this case you have \(r=3\), and you want to divide \(P(x)\) by \((x3)\)
 one year ago

richywBest ResponseYou've already chosen the best response.1
now bear with me as I have no idea how to typeset long division
 one year ago

richywBest ResponseYou've already chosen the best response.1
Alright and I have no intention on how to learn! I'll do it by hand real quick
 one year ago

mskyegBest ResponseYou've already chosen the best response.0
ya i dont know how to do it either:)
 one year ago

richywBest ResponseYou've already chosen the best response.1
haha alright I didn't want to waste time by writing out each step by hand so I just filmed it. I'll upload the photo, but if it confuses you just ask me for the video! (because it is more of a process that you have to see been done to get). I made a mistake in the last step of the video though. It's fixed in the picture. Just let me upload them real quick
 one year ago

richywBest ResponseYou've already chosen the best response.1
So basically what you do is multiply 3 by the row 3 column 1, then put that answer in row 2 column 2. Then in row 3 column 2 you put the sum of row 1 column 2 and row 2 column 2. Then repeat the process.
 one year ago

mskyegBest ResponseYou've already chosen the best response.0
oooh thats pretty simple thanx for explaining it:)
 one year ago

richywBest ResponseYou've already chosen the best response.1
no worries. And video embedding would actually be a really sweet Idea now that I think of it. I wonder if it already works.
 one year ago
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