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iluvvyyhu

  • 3 years ago

Precalc help please???:( Solving inequalities with one variable? Sign chart? *In exercises 1-6, determine the x values that cause the polynomial function to be (a)zero (b)positive (c)negative.

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  1. iluvvyyhu
    • 3 years ago
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    \[f()=(x+2)(x+1)(x-5)\]

  2. iluvvyyhu
    • 3 years ago
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    sorry it should be f(x)

  3. malical
    • 3 years ago
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    First you figure out when f(x) = 0, which occurs when (x+2) =0 or (x+1) =0 or (x-5) =0. That is pretty easy, x=-2,-1,5. Your number line is -----(-2)-----(-1)------(5)----- Pick a number left of (-2) say (-5) and input it in as f(-5)= -120 therefore The part left of (-2) is negative. The next number is between (-2) and (-1) and is therefore something like (-1.5). f(-1.5) = something positive because when you put it into (x+2) you get a positive number, and into the other two parts of the equation a negative number returns. (1)(-1)(-1) = 1. Therefore that part is positive. Doing so for the other spaces (-1) to (5) and (5) to infinity results in a negative for (-1) to (5) and a positive for (5) to infinity. Therefore: ---negative--(-2)---positive---(-1)----negative----(5)-----positive----

  4. iluvvyyhu
    • 3 years ago
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    okay i understand that but im unsure of what to put for the answers, because in the back of the book (answers) their like this, (b) -2<x<-1 or x>5 (c) x<-2 or -1<x<5? but i have no clue how they got that

  5. malical
    • 3 years ago
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    That's what I get for not fully reading the question. They just want to know when that f(x) is positive, a zero, or negative. You use the sign chart to determine when it is negative and positive. So for (a) you wish to find the zeros which are at (-2), (-1), and (5). (b) however asks for when the equation is positive. It just wants the ranges. So the sign chart says that the equation is positive from (-2) to (-1) or x is greater than (-2) but less than (-1). Therefore, -2<x<-1. You don't use an equals inequality because that would imply that both (-2) and (-1) are positive and we know those to be zeros. The second part of the answer for (b) is the second part that is positive: -5<x and then onto infinity. (c) does the same thing but with negatives instead.

  6. iluvvyyhu
    • 3 years ago
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    omg thankyou so much i wouldve failed my test tomorrow lol my teacher was no help <333

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