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anonymous
 3 years ago
pls help am doing a problem on integration,area between curves
y1=x^3, and y2=x
which one shouldd be on top?
anonymous
 3 years ago
pls help am doing a problem on integration,area between curves y1=x^3, and y2=x which one shouldd be on top?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0which one should be the top boundary?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I just graphed them and it appears to be that f(x)=x is on top of f(x)=x^3 from obviously 0 to whenever x^3=x. (1)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh thanks,and so my points of intersection are 1 and 1?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how will i use 0 now?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0which boundary should i take 1,0,1?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Just keep in mind that they intersect at 0.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What else does the question/problem say?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0calculate the area bounded by those curves with respect to x axis

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{1}?\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0will that be my boundary?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you go from 1 to 1, it's just going to be twice as much as whatever the area from 0 to 1 is.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so can i do it that way,which points do i need to pick?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0problem should have specified a bit more information... but I'd just do 0 to 1.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Since even if you did do from 1 to 1, you'd have to split up the integral because at some point they switch positions.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a bit confuse.dont know the boundary to pick now

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0anyways i can use 1 and 0 right?
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