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allikatt Group Title

If you have 400.0 mL of water at 25.00 °C and add 110.0 mL of water at 95.00 °C, what is the final temperature of the mixture?

  • one year ago
  • one year ago

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  1. ganeshie8 Group Title
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    use enthalpy formula \(q = m \ c\ \Delta t\)

    • one year ago
  2. ganeshie8 Group Title
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    energy lost by hot water = energy absorbed by cool water

    • one year ago
  3. allikatt Group Title
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    How do you set up the entire equation though?

    • one year ago
  4. ganeshie8 Group Title
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    .4 * c * (T-25) = -.11 * c * (T-95)

    • one year ago
  5. ganeshie8 Group Title
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    cancel c, solve T

    • one year ago
  6. allikatt Group Title
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    Got it. Thanks so much!

    • one year ago
  7. ganeshie8 Group Title
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    yw ! remember this while doing enthalpy related problems : q system = -q surroundings

    • one year ago
  8. allikatt Group Title
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    Actually I have one more question. Why did you use .4 and .11 instead of 400 and 110?

    • one year ago
  9. ganeshie8 Group Title
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    yeah we can use 400 and 110 also here, it doesnt matter here

    • one year ago
  10. ganeshie8 Group Title
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    ideally we must convert mL to grams. becoz in enthalpy equation, m represents mass in grams.

    • one year ago
  11. ganeshie8 Group Title
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    the conversion to grams doesnt matter here since 1 mL = 1 g, for water

    • one year ago
  12. ganeshie8 Group Title
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    the correct way of putting the equation would be : 400g * c * (T-25) = 110g * c * (T-95)

    • one year ago
  13. allikatt Group Title
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    I ended up getting 19.62 degrees, but it's incorrect :/

    • one year ago
  14. ganeshie8 Group Title
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    check ur calculation again

    • one year ago
  15. ganeshie8 Group Title
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    400g * c * (T-25) = -110g * c * (T-95) 400 * (T-25) = -110* (T-95)

    • one year ago
  16. ganeshie8 Group Title
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    im getting 40.1

    • one year ago
  17. allikatt Group Title
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    That's what I got this time too. Thank you so much! I appreciate all your help.

    • one year ago
  18. ganeshie8 Group Title
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    u getting 19.62 still ? could u show ur calculation so that i can see whats happening at ur end :)

    • one year ago
  19. allikatt Group Title
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    Nope, I got the correct answer this time. 40.1 degrees Celsius

    • one year ago
  20. ganeshie8 Group Title
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    sounds great !

    • one year ago
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