anonymous
  • anonymous
Can someone help me with this? Precalc solving inequalities with one variable? The 3x is throwing me off
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[f(x)=(x-7)(3x+1)(x+4)\]
anonymous
  • anonymous
do you need to simplify?
anonymous
  • anonymous
You actually have 2 unknowns here. Is there more to this question?

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anonymous
  • anonymous
No, you use a sign chart. @Brittni0605 And yes sorry it says *In the exercises 1-6 determine the x values that cause the polynomial functions to be (a)zero (b) positive and (c)negative @ChmE
anonymous
  • anonymous
I don't see a chart, ill let @ChmE help you.
anonymous
  • anonymous
Oh no its a sign chart that you make to solve it with lol but okay(:
anonymous
  • anonymous
so we set it equal to zero, then less than for negative, then greater than for positive. Ok. Let's start with setting it equal to zero. Do not distribute, leave the equation as is. Go to each ( ) and think what will x need to be to make this zero. Only one needs to be zero for the whole thing to be zero. There should be 3 answers. I'll give you a sec. Let me know if you didn't understand what I just said
anonymous
  • anonymous
I got 7, -1/3 and -4 ....but the -1/3 doesnt look right to me:/
anonymous
  • anonymous
Thats correct! So that solves our zero.
anonymous
  • anonymous
0
anonymous
  • anonymous
But here is where it is tricky. Say we use the number 0 which satisfies the first but not the last two. Lets see if we get a positive number. 0<(0-7)(3(0)+1)(0+4) 0<-7*1*4 0<-28 no. So the answer for 0<.... is x<-4 because that is the lowest. ***I missed typed above this is for the positive****
anonymous
  • anonymous
Now what do you think the answer will be for the negative?
anonymous
  • anonymous
ummm im a little confused now :(
anonymous
  • anonymous
I don't know how to make a sign chart. I don't ever remember having to do that.
anonymous
  • anonymous
Umm well im not sure i think i kinda get it a little better? Im sorry this is taking long btw, just my teacher never helped me lol
anonymous
  • anonymous
Oh okay I got it now(:
anonymous
  • anonymous
WAITTTTTTT!!!!!!
anonymous
  • anonymous
Plug in zero
anonymous
  • anonymous
o-o? ok lol
anonymous
  • anonymous
0>-7*1*4 negative. OMG. Now I need to rethink some things. Im so sorry. Lets try to make a sign chart.
anonymous
  • anonymous
lol okay|dw:1352178275962:dw| would i put the 1/3 on it though? i dont know lol Its bothering me since its a fraction lol
anonymous
  • anonymous
|dw:1352178252794:dw|
anonymous
  • anonymous
so when it is negative is x<-4, -1/37
anonymous
  • anonymous
okay thats easier for me to understand(:
anonymous
  • anonymous
How to solve problems like this. Set equal to zero. Solve each term for the zeros. Put those points on a number line. Pick easy numbers between those points. Test to see if it is positive or negative. Follow the number line like a map to get the solutions for neg and pos.
anonymous
  • anonymous
Sorry for leading you estray but sometimes working through a problem and finding mistakes helps us understand a little more about the correct way in terms of what is not right. I think a sign graph is very helpful, I'd continue to use that. Do you think you could do a problem like this by yourself now? Thanks for refreshing me as well. It took a while but we got it !!
anonymous
  • anonymous
Umm yes i think so(: ill practice a little more before i goto sleep lol but thanks a bunch <3
anonymous
  • anonymous
I'm in differential equations right now which is Calc 4, and I almost got this question wrong, humbling. Good luck and check your work if you have time, it's very beneficial.
anonymous
  • anonymous
Oh wow but alright(: thanks again <3

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