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ChristaB
Group Title
Find the missing coordinates in the following solution for the given equation:
Y = X2 + 2X + 1 : (3,?)
(X2 is supposed to be X squared but I haven't figured out how to do that on the puter)
 one year ago
 one year ago
ChristaB Group Title
Find the missing coordinates in the following solution for the given equation: Y = X2 + 2X + 1 : (3,?) (X2 is supposed to be X squared but I haven't figured out how to do that on the puter)
 one year ago
 one year ago

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matricked Group TitleBest ResponseYou've already chosen the best response.0
simplify by putting x=3 hence we have y=(3)^2 +2(3)+1=96+1=4 hence the missing cordinate is 4
 one year ago

ChristaB Group TitleBest ResponseYou've already chosen the best response.0
Good Lord.. was that seriously all there was to that? After all the other stuff I have been working on tonight, I seriously was making that out to be a whole lot more complicated then it actually was.
 one year ago

ChristaB Group TitleBest ResponseYou've already chosen the best response.0
Here is a really stupid question... again, its late and I have been working tirelessly on this for more then 15 hours, so I know I know the answer, but I am drawing a blank... 6 (2/3)... is that = to: 12/3
 one year ago

matricked Group TitleBest ResponseYou've already chosen the best response.0
yup 6 (2/3)... is that = to: 12/3=4
 one year ago

ChristaB Group TitleBest ResponseYou've already chosen the best response.0
Here is the actual question I am trying to answer: Y = 6x  5 : (2/3, ?) Y= 6(2/3)  5 12/3  15/3 Y = 3
 one year ago

matricked Group TitleBest ResponseYou've already chosen the best response.0
Y= 6(2/3)  5=(12/3) 5 =4 5 =9
 one year ago

ChristaB Group TitleBest ResponseYou've already chosen the best response.0
Damn.. I was way off on that one
 one year ago

ChristaB Group TitleBest ResponseYou've already chosen the best response.0
It is the multiplication of the fractions... it gets me every time
 one year ago
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