anonymous
  • anonymous
Find the missing coordinates in the following solution for the given equation: Y = X2 + 2X + 1 : (-3,?) (X2 is supposed to be X squared but I haven't figured out how to do that on the puter)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
simplify by putting x=-3 hence we have y=(-3)^2 +2(-3)+1=9-6+1=4 hence the missing cordinate is 4
anonymous
  • anonymous
Good Lord.. was that seriously all there was to that? After all the other stuff I have been working on tonight, I seriously was making that out to be a whole lot more complicated then it actually was.
anonymous
  • anonymous
Here is a really stupid question... again, its late and I have been working tirelessly on this for more then 15 hours, so I know I know the answer, but I am drawing a blank... -6 (2/3)... is that = to: -12/3

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anonymous
  • anonymous
yup -6 (2/3)... is that = to: -12/3=-4
anonymous
  • anonymous
Here is the actual question I am trying to answer: Y = -6x - 5 : (2/3, ?) Y= -6(2/3) - 5 12/3 - 15/3 Y = -3
anonymous
  • anonymous
Y= -6(2/3) - 5=-(12/3) -5 =-4 -5 =-9
anonymous
  • anonymous
Damn.. I was way off on that one
anonymous
  • anonymous
It is the multiplication of the fractions... it gets me every time

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