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ChristaB
Group Title
Find the missing coordinates in the following solution for the given equation:
Y = X2 + 2X + 1 : (3,?)
(X2 is supposed to be X squared but I haven't figured out how to do that on the puter)
 2 years ago
 2 years ago
ChristaB Group Title
Find the missing coordinates in the following solution for the given equation: Y = X2 + 2X + 1 : (3,?) (X2 is supposed to be X squared but I haven't figured out how to do that on the puter)
 2 years ago
 2 years ago

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matricked Group TitleBest ResponseYou've already chosen the best response.0
simplify by putting x=3 hence we have y=(3)^2 +2(3)+1=96+1=4 hence the missing cordinate is 4
 2 years ago

ChristaB Group TitleBest ResponseYou've already chosen the best response.0
Good Lord.. was that seriously all there was to that? After all the other stuff I have been working on tonight, I seriously was making that out to be a whole lot more complicated then it actually was.
 2 years ago

ChristaB Group TitleBest ResponseYou've already chosen the best response.0
Here is a really stupid question... again, its late and I have been working tirelessly on this for more then 15 hours, so I know I know the answer, but I am drawing a blank... 6 (2/3)... is that = to: 12/3
 2 years ago

matricked Group TitleBest ResponseYou've already chosen the best response.0
yup 6 (2/3)... is that = to: 12/3=4
 2 years ago

ChristaB Group TitleBest ResponseYou've already chosen the best response.0
Here is the actual question I am trying to answer: Y = 6x  5 : (2/3, ?) Y= 6(2/3)  5 12/3  15/3 Y = 3
 2 years ago

matricked Group TitleBest ResponseYou've already chosen the best response.0
Y= 6(2/3)  5=(12/3) 5 =4 5 =9
 2 years ago

ChristaB Group TitleBest ResponseYou've already chosen the best response.0
Damn.. I was way off on that one
 2 years ago

ChristaB Group TitleBest ResponseYou've already chosen the best response.0
It is the multiplication of the fractions... it gets me every time
 2 years ago
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