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anonymous
 4 years ago
Find the missing coordinates in the following solution for the given equation:
Y = X2 + 2X + 1 : (3,?)
(X2 is supposed to be X squared but I haven't figured out how to do that on the puter)
anonymous
 4 years ago
Find the missing coordinates in the following solution for the given equation: Y = X2 + 2X + 1 : (3,?) (X2 is supposed to be X squared but I haven't figured out how to do that on the puter)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0simplify by putting x=3 hence we have y=(3)^2 +2(3)+1=96+1=4 hence the missing cordinate is 4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Good Lord.. was that seriously all there was to that? After all the other stuff I have been working on tonight, I seriously was making that out to be a whole lot more complicated then it actually was.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Here is a really stupid question... again, its late and I have been working tirelessly on this for more then 15 hours, so I know I know the answer, but I am drawing a blank... 6 (2/3)... is that = to: 12/3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yup 6 (2/3)... is that = to: 12/3=4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Here is the actual question I am trying to answer: Y = 6x  5 : (2/3, ?) Y= 6(2/3)  5 12/3  15/3 Y = 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Y= 6(2/3)  5=(12/3) 5 =4 5 =9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Damn.. I was way off on that one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is the multiplication of the fractions... it gets me every time
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