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anonymous
 3 years ago
lim x>infinite 1/x^2 S(integral sign) tan^1 dt
anonymous
 3 years ago
lim x>infinite 1/x^2 S(integral sign) tan^1 dt

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ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x\to \infty} \frac 1 {x^2} \int \tan^{1} t\ dt\]Is this your question?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes sorry Im new to this :)

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0The integral doesn't involve x, so it can be taken out. \[\int \tan^{1} t\ dt\times \lim_{x\to \infty} \frac 1 {x^2} \] tell me what's \[\frac 1 \infty=???\]

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0nope \[\frac 1 0= \infty\] so \[\frac 1 \infty=???\]

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0good :D \[\int \tan^{1} t\times 0=???\]

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0if you multiply 0 by tan t then what you'd get?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what ? the answer is 0 :) Ok it makes since if you put it that way but for me whos math retarded its difficult:)

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0You know the integral is a variable of t, if you integrate it and multiply by zero. You'd get zero. So it's not necessary to integrate. It's 0

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0I doubt that this is so easy. I think you have missed some portion of the question. Maybe limits on the integral. Could you check the question again?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its just as you put it so I think this is right but I have one more :) its \[\int\limits_{}^{} \frac{ (x^3)\ }{(x1)^2(x+2) }\] Can you help me with that?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0okay, did you try this?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I dont know what to do :) should I start by divide ?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0What's the expansion of (x1)^2?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0What would you get if you multiply these?

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0\[(x1)\times (x1)=???\]

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0Good:) Numerator we have x^2, so add and subtract (2x+1) Could you rewrite the integral using this?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{} \frac{ x }{2x+1 } \] Im I on the right way? I know Im not very good at this at all :)

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.0I'm sorry, i thought it's x^2 in numerator Sorry. Let me think about this
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