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ash2326 Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x\to \infty} \frac 1 {x^2} \int \tan^{1} t\ dt\]Is this your question?
 2 years ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
yes sorry Im new to this :)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
No need to be sorry :)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
The integral doesn't involve x, so it can be taken out. \[\int \tan^{1} t\ dt\times \lim_{x\to \infty} \frac 1 {x^2} \] tell me what's \[\frac 1 \infty=???\]
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
@tjutta ???
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
nope \[\frac 1 0= \infty\] so \[\frac 1 \infty=???\]
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
good :D \[\int \tan^{1} t\times 0=???\]
 2 years ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
SIN/COS ? :)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
if you multiply 0 by tan t then what you'd get?
 2 years ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
what ? the answer is 0 :) Ok it makes since if you put it that way but for me whos math retarded its difficult:)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
You know the integral is a variable of t, if you integrate it and multiply by zero. You'd get zero. So it's not necessary to integrate. It's 0
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
I doubt that this is so easy. I think you have missed some portion of the question. Maybe limits on the integral. Could you check the question again?
 2 years ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
its just as you put it so I think this is right but I have one more :) its \[\int\limits_{}^{} \frac{ (x^3)\ }{(x1)^2(x+2) }\] Can you help me with that?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
okay, did you try this?
 2 years ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
I dont know what to do :) should I start by divide ?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
What's the expansion of (x1)^2?
 2 years ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
(x1)(x+1) ?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
What would you get if you multiply these?
 2 years ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
ok I only have 2 ?
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
\[(x1)\times (x1)=???\]
 2 years ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
x^2  2x + 1
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
Good:) Numerator we have x^2, so add and subtract (2x+1) Could you rewrite the integral using this?
 2 years ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{} \frac{ x }{2x+1 } \] Im I on the right way? I know Im not very good at this at all :)
 2 years ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
I'm sorry, i thought it's x^2 in numerator Sorry. Let me think about this
 2 years ago
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