A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
lim x>infinite 1/x^2 S(integral sign) tan^1 dt
anonymous
 4 years ago
lim x>infinite 1/x^2 S(integral sign) tan^1 dt

This Question is Closed

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x\to \infty} \frac 1 {x^2} \int \tan^{1} t\ dt\]Is this your question?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes sorry Im new to this :)

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0The integral doesn't involve x, so it can be taken out. \[\int \tan^{1} t\ dt\times \lim_{x\to \infty} \frac 1 {x^2} \] tell me what's \[\frac 1 \infty=???\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0nope \[\frac 1 0= \infty\] so \[\frac 1 \infty=???\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0good :D \[\int \tan^{1} t\times 0=???\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0if you multiply 0 by tan t then what you'd get?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what ? the answer is 0 :) Ok it makes since if you put it that way but for me whos math retarded its difficult:)

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0You know the integral is a variable of t, if you integrate it and multiply by zero. You'd get zero. So it's not necessary to integrate. It's 0

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0I doubt that this is so easy. I think you have missed some portion of the question. Maybe limits on the integral. Could you check the question again?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its just as you put it so I think this is right but I have one more :) its \[\int\limits_{}^{} \frac{ (x^3)\ }{(x1)^2(x+2) }\] Can you help me with that?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0okay, did you try this?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I dont know what to do :) should I start by divide ?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0What's the expansion of (x1)^2?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0What would you get if you multiply these?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0\[(x1)\times (x1)=???\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0Good:) Numerator we have x^2, so add and subtract (2x+1) Could you rewrite the integral using this?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{} \frac{ x }{2x+1 } \] Im I on the right way? I know Im not very good at this at all :)

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.0I'm sorry, i thought it's x^2 in numerator Sorry. Let me think about this
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.