Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
\[\lim_{x\to \infty} \frac 1 {x^2} \int \tan^{1} t\ dt\]Is this your question?
 one year ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
yes sorry Im new to this :)
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
No need to be sorry :)
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
The integral doesn't involve x, so it can be taken out. \[\int \tan^{1} t\ dt\times \lim_{x\to \infty} \frac 1 {x^2} \] tell me what's \[\frac 1 \infty=???\]
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
@tjutta ???
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
nope \[\frac 1 0= \infty\] so \[\frac 1 \infty=???\]
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
good :D \[\int \tan^{1} t\times 0=???\]
 one year ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
SIN/COS ? :)
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
if you multiply 0 by tan t then what you'd get?
 one year ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
what ? the answer is 0 :) Ok it makes since if you put it that way but for me whos math retarded its difficult:)
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
You know the integral is a variable of t, if you integrate it and multiply by zero. You'd get zero. So it's not necessary to integrate. It's 0
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
I doubt that this is so easy. I think you have missed some portion of the question. Maybe limits on the integral. Could you check the question again?
 one year ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
its just as you put it so I think this is right but I have one more :) its \[\int\limits_{}^{} \frac{ (x^3)\ }{(x1)^2(x+2) }\] Can you help me with that?
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
okay, did you try this?
 one year ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
I dont know what to do :) should I start by divide ?
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
What's the expansion of (x1)^2?
 one year ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
(x1)(x+1) ?
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
What would you get if you multiply these?
 one year ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
ok I only have 2 ?
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
\[(x1)\times (x1)=???\]
 one year ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
x^2  2x + 1
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
Good:) Numerator we have x^2, so add and subtract (2x+1) Could you rewrite the integral using this?
 one year ago

tjutta Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{} \frac{ x }{2x+1 } \] Im I on the right way? I know Im not very good at this at all :)
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
I'm sorry, i thought it's x^2 in numerator Sorry. Let me think about this
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.